function compareArrays(arr1, arr2) { return JSON.stringify(arr1) === JSON.stringify(arr2); } const array1 = [1, 2, 3]; const array2 = [2, 1, 3]; console.log(compareArrays(array1, array2)); // Output: true 以上是比较两个数组并返回true的几种常见方法。根据具体的业务需求和数据...
Compare two arrays Demo Code Array.prototype.equals =function(array) {for(vari = 0; i < this.length; i++){if(this[i] != array[i]){returnfalse; }/*fromwww.java2s.com*/}returntrue; } Previous Next Related Tutorials Flatten array into string ...
there's a framework conflict or you've got double inclusions in your code.");//attach the .equals method to Array's prototype to call it on any arrayArray.prototype.equals =function(array) {//if the other array is a falsy value, returnif(!array)returnfalse;//compare lengths...
var y = [1,3,2,4,5]; alert(y.sort(compare)); //1,2,3,4,5alert(y.sort(compare).reverse()); //5,4,3,2,1 对于数值类型或者其valueOf()方法会返回数值类型的对象类型,可以使用一个更简单的比较函数。 升序: function compare(value1,value2) { return value1-value2; }; 1. 2. 3....
array.concat(array1[, array2, ...])将一个或多个数组连接到原始数组。如下所示,连接两个数组: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 constheroes=['小智','前端小智'];constvillains=['老王','小三'];consteveryone=heroes.concat(villains);everyone// ["小智", "前端小智", "老王",...
10 // compare lengths - can save a lot of time 11 if (this.length != array.length) 12 return false; 13 14 for (var i = 0, l = this.length; i < l; i++) { 15 // Check if we have nested arrays 16 if (this[i] instanceof Array && array[i] instanceof Array) { ...
{ "name": "orange" }] json2 = [{ "name": "apple" }, { "name": "mango" }] I need to compare the two jsons and find out the mismatch between two json-arrays. The expected result is obviously orange. Would you please anyone help me getting this done. ...
myarr2.sort(mycompare); console.log(myarr2);//(4) [3, 8, 10, 25] 1 2 3 4 5 6 7 8 9 比较函数的参数 比较函数会接受两个参数,并对两者进行比较 若第一个参数应位于第二个参数之前,则返回一个负数 若第一个参数等于第二个参数,则返回0 ...
我有两个arrays的JavaScript对象: const typeCrop = [ { id: 1, name: 'apple' }, { id: 2, name: 'pineapple' }, { id: 3, name: 'orange' }, { id: 4, name: 'berry' }, ] const lands = [ { landOwnerId: 6, landId: 1, landTypeID: 1, area: 3800 }, ...
length; i++) { // Check if we have nested arrays if (this[i] instanceof Array && array[i] instanceof Array) { // recurse into the nested arrays if (!this[i].compare(array[i])) return false; } else if (this[i] != array[i]) { // Warning - two different object instances ...