方法一: Array.prototype.unique=function(){vararr=[];//新建一个临时数组for(vari=0;i<this.length;i++){//遍历当前数组if(arr.indexOf(this[i])==-1){//当前数组的第i个值在新数组中找不到,则添加到新数组中去arr.push(this[i]); } }returnarr; }; 方法二: Array.prototype.unique=function...
方法一:.Array.prototype.unique=function(){ var arr=[];//新建一个临时数组 for(var i=0;i<this.length;i++){//遍历当前数组 if(arr.indexOf(this[i])==-1){//当前数组的第i个值在新数组中找不到,则添加到新数组中去 arr.push(this[i]); } } return arr; }; 方法二:Array.prototype.uni...
Array.prototype.unique=function(){ var arr=[];//新建⼀个临时数组 for(var i=0;i<this.length;i++){//遍历当前数组 if(arr.indexOf(this[i])==-1){//当前数组的第i个值在新数组中找不到，则添加到新数组中去 arr.push(this[i]); } } return arr;...
AI代码解释 // 思路:获取没重复的最右一值放入新数组vararr=[1,3,5,7,9,1,3,5];functionunique5(array){varr=[];for(vari=0,l=array.length;i<l;i++){for(varj=i+1;j<l;j++)if(array[i]===array[j])j=++i;r.push(array[i]);}returnr;}console.log(unique5(arr)); 效果如下: 图...
functon unique(arr) {let res = []for (let i = 0; i < arr.length; i++) {if (res.indexOf(arr[i]) === -1) {res.push(arr[i])}}return res} 利用indexOf检测元素在数组中第一次出现的位置是否和元素现在的位置相等，如果不等则说明该元素是重复元素 function unique(arr) {if (!Array...
function uniqueArray(arr) { let unique = []; for(let i = 0; i < arr.length; i++) { if(unique.indexOf(arr[i]) === -1) { unique.push(arr[i]); } } return unique; } let array = [1, 2, 2, 3, 4, 4, 5]; console.log(uniqueArray(array)); // 输出: [1, 2, 3,...
channel.pushMessage(param);if( !! channel) {channel.add(uid, sid);}cb(this.get(name, flag));};/*** Get user from chat channel.** @param {Object} opts parameters for request* @param {String} name channel name* @param {boolean} flag channel parameter* @return {Array} users uids ...
routingRules {Array} res {Object} response info, including status {Number} response status headers {Object} response headers size {Number} response size rt {Number} request total use time (ms).deleteBucketWebsite(name[, options])Delete the bucket website config.parameters...
The first is number of consecutive failed attempts by the same user unique ID/name and IP address. The second is number of failed attempts from an IP address over some long period of time. For example, block an IP address if it makes 100 failed attempts in one day. Otherwise: An attack...
push({key: target[ti], value: 0}); ++ti; } } if(oi<orig.length) Array.prototype.push.apply(result, orig.slice(oi)); if(ti<target.length) Array.prototype.push.apply(result, target.slice(ti).map(t => ({key: t, value: 0}))); return result; } }; } Fill missing numeric-...