每个岗位包含部门ID(deptId)、岗位ID(postId)和岗位名称(postName)5* @param {Array} array2 部门信息数组,每个部门包含部门ID(id)和部门名称(label)6* @returns {Array} 返回一个新数组,每个元素代表一个部门,包含部门ID、部门名称和该部门下的所有岗位(children)7*/8mergeArrays(array1, array2)...
functionmergeArrays(arr1,arr2){varmerged=[];varpropMap={};// 遍历第一个数组,将属性添加到merged和propMap中for(vari=0;i<arr1.length;i++){varprop=arr1[i];merged.push(prop);propMap[prop.key]=prop;}// 遍历第二个数组,检查属性是否已存在于propMap中for(varj=0;j<arr2.length;j++){var...
const arrayToMap = (arr) => { const mergeObj = (s1, s2) => { const keys = Object.keys(s1); for (const key of keys) { if (typeof s1[key] !== "number" || key === "dept_id") continue; s1[key] += s2[key]; s1[key] /= 2; } }; const map = new Map(); for (...
$d = array_merge($a,$b,$c);//1.先合并数组 $d = array_flip($d);//2.反转数组,会达到去重键 $d = array_flip($d);//3.再反转数组...1002 [5] => 1003 [6] => 1004 [7] => 1005 ) sort($d);//方法一:重新以升序排序(更灵活) $d = array_merge($d);//方法二:重新合并达...
def[i] = mergeObjs(def[i], obj[i]); } // if its an array, simple values need to be joined. Object values need to be remerged. else if(obj[i] != null && (obj[i] instanceof Array) && obj[i].length > 0) { // test to see if the first element is an object or not so...
Step 3 : iterate the second array to it's length using for loop. Step 3.1 : Push the each items of array2 in array1 using array.push method as follows: array1.push(array2[i]); Step 4 : Print the array1 as result. Step 5 : Stop the process. Program function mergeTwoArrays(array...
1.使用Array.prototype.push apply() 添加第二个数组的所有元素。 arr.push(element1, ..., elementN) 注意当第二个数组(如示例中的moreVegs)太大时不要使用这个方法来合并数组,因为事实上一个函数能够接受的参数个数是有限制的。具体可以参 经验分享 转载 oo尖子oo 2021-06-28 14:09:51 1454阅读 ja...
merge(obj, [ {status: "funky", errors: 1}, {status: "groovy", errors: 2}, {status: "sweet"}]); // returns Immutable({status: "sweet", errors: 2}) // because passing an Array is shorthand for // invoking a separate merge for each object in turn. Returns an Immutable Object ...
{ // docs is an array containing document Earth only }); // Use the dot-notation to match fields in subdocuments db.find({ "humans.genders": 2 }, function (err, docs) { // docs contains Earth }); // Use the dot-notation to navigate arrays of subdocuments db.find({ "complete...
Returns:Array.<H3Index>- H3 indexes for all hexagons in ring Throws: H3ErrorIf input is invalid or output is too large for JS h3.gridDiskDistances(h3Index, ringSize) ⇒Array.<Array.<H3Index>> Get all hexagons in a k-ring around a given center, in an array of arrays ordered by...