]; let uniqueArr = Array.from(new Set(jsonArr.map(JSON.stringify))).map(JSON.parse); console.log(uniqueArr); // 输出 [{id: 1, name: "apple"}, {id: 2, name: "banana"}, {id: 3, name: "orange"}] 方法二:使用jQuery的$.unique()方法进行去重 let jsonArr = [ {id: 1, name...
* 数据对象是json对象去除重复的项,首先不能直接将整个数组转成字符串 * 先定义一个新数组,把原数组的每一个对象通过JSON.stringify( attr2[i]) 添加到新数组中去,此时添加进去的每一个不是对象了是个字符串 * 新数组循环比较两个字符串(注意只能是字符串)是否相等,相等删除 * */ var attr2 = [{ "dy...
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vararr = [ {"name":"1","value":"qqq","age":"10"}, {"name":"1","value":"qqq","...
js 数组对象去重 let hash ={}; let config=[ { name:2, state:true, output: 'Y'}, { name:3, state:true, output: 'A'}, { name:5, state:true, output: 'S'}, { name:7, state:true, output: 'B'} ]; config= [...config, {//合并数组 ...运算符即为数组展开运算符name: 3,...
1.js 数组中去除重复的json对象 <!DOCTYPE html> varlist =[{"name":"123"}, {"name":"123"}, {"name":"456"}]varlist2 =[{"dy":2017,"dm":2,"dd":20}, {"dy":2018,"dm":2,"dd":20}, {"dy":2018,"dm":2,"dd":20}, {"dy":2017,"dm":2,"dd"...