List<String> strings = List.of("Java", "is", "cool"); String message = String.join(" ", strings); // message returned is: "Java is cool" Set<String> strings = new LinkedHashSet<>(List.of("Java", "is", "very", "cool")); String message = String.join("-", strings); //...
public static void main(String[] args) { //数组转集合 Arrays.asList List<String> strings = Arrays.asList(new String[]{"aa", "bb", "cc"}); //集合转数组 Object[] objects = strings.toArray(); ArrayList<Integer> list = new ArrayList<>(); list.add(1); list.add(4); list.add(1...
同时,这里有一个修复的补丁代码示例: publicStringjoinStrings(List<String>strings){if(strings==null||strings.isEmpty()){return"";}returnstrings.stream().collect(Collectors.joining(","));} 1. 2. 3. 4. 5. 6. 扩展应用 随着Java 8后的不断发展,字符串处理的需求不仅限于简单的连接,还逐渐被应用...
List<String>tokens=Arrays.asList("How","To","Do","In","Java");StringjoinedString=tokens.stream().collect(Collectors.joining(",","[","]"));System.out.println(joinedString);//[How,To,Do,In,Java] 4. Apache Commons – UsingStringUtils.join() TheStringUtilsclass of theApache Commons Lan...
Stringmessage=String.join("-","Java","is","cool"); //messagereturned is:"Java-is-cool"List<String> strings = new LinkedList<>(); strings.add("Java");strings.add("is"); strings.add("cool");Stringmessage=String.join(" ", strings); ...
String message = String.join(" ", strings);// message returned is: "Java is cool"Set<String> strings = new LinkedHashSet<>(List.of("Java", "is", "very", "cool"));String message = String.join("-", strings);// message returned is: "Java-is-very-cool"参考资料：[1] jdk15.0....
result = "".join(strings) 这里的操作是线性的,时间复杂度为 O(n)。 解决方案示例 假设我们有一个包含大量字符串的列表,我们想要将它们连接成一个单一的字符串: 代码语言:txt 复制 # 使用 + 运算符(不推荐) result = "" for s in large_list_of_strin...
text.add("is"); text.add("fun"); String result; result = String.join("-", text); System.out.println(result);// Java-is-fun} } Run Code Here, anArrayListofStringtype is created. The elements of array list are joined using the-delimiter....
在上述代码中，首先通过list的iterator()方法获取一个Iterator对象，然后使用该对象遍历list的所有元素。代...
方法需要返回的是List <String>，但是这里只有List<Category>,此时就要想到stream().map public List<...