3.Check for Palindromes 如果给定的字符串是回文,返回true,反之,返回false。 如果一个字符串忽略标点符号、大小写和空格,正着读和反着读一模一样,那么这个字符串就是palindrome(回文)。 注意你需要去掉字符串多余的标点符号和空格,然后把字符串转化成小写来验证此字符串是否为回文。 函数参数的值可以为"racecar",...
Algorithm Step 1: We have to find out if the given string is a palindrome or not. So to do this task we will create a function called isPalindrome and in this function, we will pass a parameter of string as str. So for this str, we will check the palindrome condition. Step 2:...
判断某个字符串是否为回文字符串,譬如racecar与race car都是回文字符串: isPalindrome("racecar"); // true isPalindrome("race Car"); // true function isPalindrome(word) { // Replace all non-letter chars with "" and change to lowercase var lettersOnly = word.toLowerCase().replace(/\s/g,...
Check for Palindrome function isPalindrome(str) { return str === str.split('').reverse().join(''); } console.log(isPalindrome("racecar")); // Output: true Write a function to calculate the factorial of a number. function factorial(n) { if (n === 0 || n === 1) { return...
isPalindrome("racecar"); // trueisPalindrome("race Car"); // truefunction isPalindrome(word) { // Replace all non-letter chars with "" and change to lowercase var lettersOnly = word.toLowerCase().replace(/\s/g, ""); // Compare the string with the reversed version of the string ...
2. Check Palindrome Write a JavaScript function that checks whether a passed string is a palindrome or not? A palindrome is word, phrase, or sequence that reads the same backward as forward, e.g., madam or nurses run. Click me to see the solution ...
B Palindrome - check if the string is the same in reverse A Levenshtein Distance - minimum edit distance between two sequences A Knuth–Morris–Pratt Algorithm (KMP Algorithm) - substring search (pattern matching) A Z Algorithm - substring search (pattern matching) A Rabin Karp Algorithm - sub...
function isPalindrome(str) { // special case if (str.length === 1) return true; if (str.length === 2) return str[0] === str[1]; // base case // String.prototype.slice(-1): extract the last element if (str[0] === str.slice(-1)) { return isPalindrome(str.slice(1, -...
Check for palindrome (检查回文) 使用toLowerCase() 转换字符串,并使用 replace() 从中删除非字母数字字符。然后,在将其转换为 tolowerCase() 之后,将 split('') 为单独的字符,reverse() ,join('')并与原始非反转字符串进行比较。 JavaScript 代码: ...
function checkPalindrome(n){const t=string.length;for(let n=0;n<t/2;n++) if(string[n]!==string[t-1-n])return"It is not a palindrome";return"It is a palindrome"} const string=prompt("Enter a string: "), value=checkPalindrome(string);console.log(value); Wie du sehen kannst, is...