(9) -> 9 is an odd number. ("15") -> Parameter value must be number! Sample Solution: JavaScript Code: // Define a function to check whether a number is even or oddconstcheck_even_odd=(n)=>{// Check if the input is not a numberif(typeofn!="number"){return'Parameter value ...
// program to check if the number is even or odd// take input from the userconstnumber = prompt("Enter a number: ");// ternary operatorconstresult = (number %2==0) ?"even":"odd";// display the resultconsole.log(`The number is${result}.`); Run Code Output Enter a number: 5...
0,code:!0,charCode:!0,key:!0,keyCode:!0,button:!0,buttons:!0,clientX:!0,clientY:!0,offsetX:!0,offsetY:!0,pointerId:!0,pointerType:!0,screenX:!0,screenY:!0,targetTouches:!0,toElement:!0,touches:!0,which:function(e){var t=e.button;return null==e.which&&be.test(e.type)?
Moreover, whether you are new to JavaScript or more professional developers, learning new knowledge is always a good thing. This article has compiled some very useful single lines of code (20+), these single lines of code can help you improve your work efficiency and can help debug your cod...
class BusinessError extends Error {constructor(code, message, { cause }) {super(message);this.code= code;this.cause= cause;}}async function addName() {const { ctx } = this;try {constres=awaitctx.fetch('http://examples.com/getxxx');return res.json();} catch (e) {throw new Business...
The string either contains all odd numbers and only one even number or all even numbers and only one odd number. Our function should return that one different number from the string. Advertisement - This is a modal window. No compatible source was found for this media. ...
Learn how to find the difference between odd and even indexed elements in JavaScript with practical examples and code snippets.
Try the following code without memo and with memo.const fib = (n) => { if (n < 2) return n; return fib(n - 1, memo) + fib(n - 2, memo); }; console.log(fib(40)); // Browser crash or timeout const fib = (n, memo = {}) => { if (n < 2) return n; if (memo...
{ border: "none,none,none,thin #333333"}); var oddRow=excel.addStyle ( { fill: "#ECECEC" ,border: "none,none,none,thin #333333"}); for (var i=1;i<50;i++) excel.set({row:i,style: i%2==0 ? evenRow: oddRow }); excel.set({row:3,value: 30 }); var headers=["...
Even the fastest code in a loop body will add up when iterated thousands of times. Additionally, there is a small amount of performance overhead associated with executing a loop body, which just adds to the overall execution time. Decreasing the number of iterations throughout the loop can th...