constshallowCopy=Object.assign({},simpleEvent)constshallowCopy=Object.create(simpleEvent) 但是一旦我们有了嵌套项目,我们就会遇到麻烦: constcalendarEvent={title:"Builder.io Conf",date:newDate(123),attendees:["Steve"]}constshallowCopy={...calendarEvent}// 🚩 哎呀 - 我们刚刚把"Bob"添加到了复制品...
function deepClone(obj) { if (obj === null || typeof obj !== 'object') { retur...
constshallowCopy=Object.assign({},simpleEvent)constshallowCopy=Object.create(simpleEvent) 但是一旦我们有了嵌套项,我们就会遇到麻烦: 代码语言:javascript 复制 constcalendarEvent={title:"Builder.io Conf",date:newDate(123),attendees:["Steve"]}constshallowCopy={...calendarEvent}shallowCopy.attendees.push(...
1 JavaScript deep copy of an object graph 2 How to deep copy (clone) an object with array members in Javascript? 11 How to deep copy a custom object in JavaScript? 0 Deep Clone ImageData JavaScript 1 How to make a deep copy of a object in Javascript 1 Deep copy object with Dept...
使用 JSON.parse 和 JSON.stringify:constoriginalObject={a:1,b:{c:2}};constdeepCopyObject=JSON....
However theobjobject is retaining a shallow copy of thethis.formDialog.inputsobject, when I expect it to make a deep copy of it. Why is it not creating a deep copy of the object even though I am usingJSON.parse(JSON.stringify(obj))?
letmyArray=[1,2,3,4];letdeepCopy=structuredClone(myArray); 现在我们已经用深度拷贝创建了新的数组,我们不再需要担心在改变拷贝时弄乱了原始数组。 结论 浅层拷贝是相当令人困惑的,也是Javascript的众多怪癖之一。了解它们是什么,可以在将来调试时省去很多麻烦,而使用深度拷贝是避免这些问题的一个好办法。
//javascriptfunctiondeepCopyUsingJson(obj){returnJSON.parse(JSON.stringify(obj));} 2. 使用递归函数 这种方法更通用,能够处理包含复杂嵌套和各种数据类型的对象,包括函数和循环引用(需额外处理): //javascriptfunctiondeepCopyUsingRecursion(obj){if(obj===null||typeofobj!=='object'){returnobj;}constcopy=...
JavaScript provides us with various built-in methods to copy an object, but the shallow copy is the default behavior in most of them. Shallow Copy Methods in JavaScript We will briefly cover the shallow copy methods to make you aware of some of the wrong ways to deep copy. Use the ...
So if you don't want every modificationobj2affectobj1, then we can make a deep copy ofobj1and play with it: const obj2 = JSON.parse(JSON.stringify(obj1)); obj2.name = '金毛2' console.log(obj1) // {name: '金毛1', city: '上海'} ...