// Code to execute if condition2 is true } else { // Code to execute if all conditions are false } 在这个if-else if语句中,如果“condition1”是true,第一个代码块就会执行。如果“condition1”是false,但“condition2”是true,第二个代码块就会执行。如果所有条件都为false,最后一个代码块就会执行。
const conditions = [value1, value2]; const actions = [ () => { // 执行代码块1 }, () => { // 执行代码块2 }, ]; const index = conditions.indexOf(expression); if (index !== -1) { actions[index](); // 根据条件值执行相应的代码块 } 使用三元运算符:如果条件判断的结果只有两...
You start by checking if a particular condition is met. If that condition hasn’t been met, you can check if another condition is met. Finally, if none of the previous conditions are met, you can use the else statement to run additional code. Below is an example of how you would wri...
office.js:76 Uncaught Error: Office.js has not fully loaded. Your app must call "Office.onReady()" as part of it's loading sequence (or set the "Office.initialize" function). If your app has this functionality, try reloading this page. ...
This section only applies to Interactive Server components, but client-side components may also set JS interop timeouts if conditions warrant it.In server-side apps with server interactivity, JavaScript (JS) interop may fail due to networking errors and should be treated as unreliable. Blazor...
functionshowList(employees){employees.forEach(employee=>{varexpectedSalary=employee.calculateExpectedSalary();varexperience=employee.getExperience();varportfolio;if(employee.type==='manager'){portfolio=employee.getMBAProjects();}else{portfolio=employee.getGithubLink();}vardata={expectedSalary:expectedSalary...
If there is no match, the default code block is executed. Example ThegetDay()method returns the weekday as a number between 0 and 6. (Sunday=0, Monday=1, Tuesday=2 ..) This example uses the weekday number to calculate the weekday name: ...
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// bad var count = 1; if (true) { count += 1; } // good, use the let. let count = 1; if (true) { count += 1; }2.3 注意: let、const都是块级作用域 // const and let only exist in the blocks they are defined in. { let a = 1; const b = 1; } console.log(a);...
if (tree1.val === tree2.val) { // recursively compare the left and right subtrees return compareTrees(tree1.left, tree2.left) && compareTrees(tree1.right, tree2.right); } } // if any of the above conditions are not met, return false ...