Index.js 代码语言:javascript 代码运行次数:0 运行 AI代码解释 constfs=require('fs');constpath=require('path');constpostsUrl=path.join(__dirname,'db/posts.json');constcommentsUrl=path.join(__dirname,'db/comments.json');//return the data from our filefunctionloadCollection(url,callback){fs....
const url = document.getElementById('queryURL').value;const myData = tf.data.csv(url); ***1***await myData.take(10).forEach(x => console.log(JSON.stringify(x))); ***2***// Output is like// {"crim":0.26169,"zn":0,"indus":9.9,"chas":0,"nox":0.544,"rm":6.023, ......
使用Bun.file(),可以在特定路径下轻松加载文件: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 // Bun (index.ts)constfile=Bun.file("test.txt");constcontents=awaitfile.text();// Node.jsconstfsPromises=require('fs').promises;asyncfunctionreadFile(filePath){constdata=awaitfsPromises.readFile(...
默认的文件加载器是fs.readFileSync,如果你想要的自定义它, 设置ejs.fileLoader即可。 letejs=require('ejs');letmyFileLoader=function(filePath){return'myFileLoader: '+fs.readFileSync(filePath);};ejs.fileLoader=myFileLoad; 使用此功能,您可以在读取模板之前对其进行预处理。
else if (window.navigator.userAgent.indexOf("Firefox") >= 1) { if (obj.files) { return obj.files.item(0).getAsDataURL(); } return obj.value; } return obj.value; } } //以下即为完整客户端路径 var filepath=getPath(document.getElementById("iptfileupload")); ...
var getFilename = function (str) { return str.substring(str.lastIndexOf('/')+1); } var fileName = getFilename("C:/users/arpit/file1.txt"); console.log("FileName:",fileName); Output: FileName: file1.txt Using replace() method To get filename from path, we can use replace(...
I can use $.evalFile(file) if I fully qualify the file to run. i.e. $.evalFile("C:/temp/name.js"); But I want to run the file based on the location of the currently running javascript. I cannot seem to find a way to get access to the DOM object to determine anything. I ...
{SCRIPT PATH AND FILE NAME (.js)} 占位符是 wwwroot 下的路径和文件名。 在以下实例中,外部 JS 文件 (script.js) 置于类库的 wwwroot 文件夹中。 module 是组件类 (private IJSObjectReference? module;) 的私有可为空 IJSObjectReference。 C# 复制 module = await js.InvokeAsync<IJSObjectReference>(...
var filename = filepath.slice(idx); or var idx = filepath.lastIndexOf("\")+1;var filename = filepath.slice(idx);Friday, October 29, 2010 12:11 PMWe need a little bit more information to understand exactly what you need.Could you please tell us if the image path that you need ...
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