constarray=[3,8,12,6,10,2];// Find 10 in the given array.functioncheckForN(arr,n){for(leti=0;i<array.length;i++){if(n===array[i]){return`${true}${n}exists at index${i}`;}}return`${false}${n}does not exist in the given array.`;}checkForN(array,10); 这就是线性搜索...
To check if any element is present in the array, we can find the index of that element and check ifindex >= 0, then the element exists, else it doesn’t. The lastIndexOf method This method returns the index of the last occurrence of matched element in the array. This method searches...
constarray=[1,2,3,4,5];constvalue=3;if(array.indexOf(value)!==-1){console.log("数组中存在该值");}else{console.log("数组中不存在该值");} 使用some()方法: some()方法用于检查数组中是否有元素满足某个条件,如果有则返回true,否则返回false。
element){// Iterate through the arrayfor(vari=0;i<arr.length;i++){// Check if the current element is equal to the target elementif(arr[i]===element){// Return true if the element is found in the arrayreturntrue;}}// Return false if the element is not found in the arrayreturnfa...
Note that "inArray" is a misnomer, because it doesn't return boolean value - it returns index of first element found. So if you are checking if element exists you should use if (-1 != $.inArray(...)) ...– johndodo 2 days ago add a comment up vote31down vote First, implement...
//code to check if a value exists in an array using javascript indexOf var fruits_arr = ['Apple', 'Mango', 'Grapes', 'Orange', 'Fig', 'Cherry']; var string = "Orange"; // Find in Array fruits_arr.indexOf('Tomato'); fruits_arr.indexOf('Grapes'); // Find in String string...
Find the element that appears once in sorted array JavaScript - Suppose, we have a sorted array of literals like this −const arr = [2, 2, 3, 3, 3, 5, 5, 6, 7, 8, 9];We are required to write a JavaScript function that takes in one such array and return
constarray= [1,2,3,4]consttargetEl =array.find((num) => num >2)// 3 find方法是从后往前查找符合条件的元素,如果我们想从后往前查找符合条件的元素怎么办?是的,你可以选择 array.findLast constarray= [1,2,3,4]consttargetEl =...
find方法是从后往前查找符合条件的元素,如果我们想从后往前查找符合条件的元素怎么办?是的,你可以选择 array.findLast constarray= [1,2,3,4]consttargetEl =array.findLast((num) => num >2)// 4 3.findLastIndex 我想您已经猜到了,我们已经可以使用 findLastIndex 来查找数组末尾的匹配元素了。
Alternatively, you can use theArray.find()method. #Array.push() Element if does not exist using Array.find() This is a three-step process: Use theArray.find()method to iterate over the array. On each iteration, check if the specified value exists in the array. ...