functionsortArray(array) {// Divide and conquer by splitting the sorting logic.const sortedLeft = mergeSort(array.slice(, array.length / 2));const sortedRight = mergeSort(array.slice(array.length / 2));// Merge the sorted parts.return merge(sortedLeft, sortedRight);}functionmergeSort(array...
-(arr[i-1]-arr[i]):direction;// If it's the last element in the array, return 0 if the array is sorted, otherwise return the directionif(i===arr.length-1)return!direction?0:direction;// If the current element and the next one violate the sorting order, return 0elseif((val-a...
If the result is positive,bis sorted beforea. If the result is 0, no changes are done with the sort order of the two values. Example: The compare function compares all the values in the array, two values at a time(a, b).
const arr = [1, 2, [4, 5], 6, 7, [8]]; // 使用 map 对每个元素进行操作并用 flat 展平结果 const result = arr.map(element => Array.isArray(element) ? element : [element]).flat(); console.log(result); // output: [1, 2, 4, 5, 6, 7, 8]使用 flatmap const arr =...
Experimental: This is an experimental technology Check the Browser compatibility table carefully before using this in production. group(function(element, index, array) {}, thisArg) 代码语言:javascript 代码运行次数:0 运行 AI代码解释 const array = [1, 2, 3, 4, 5]; array.group((num, index, ...
constarray=[3,8,12,6,10,2];// Find 10 in the given array.functioncheckForN(arr,n){for(leti=0;i<array.length;i++){if(n===array[i]){return`${true}${n}exists at index${i}`;}}return`${false}${n}does not exist in the given array.`;}checkForN(array,10); ...
Check if an object is an array: constfruits = ["Banana","Orange","Apple","Mango"]; letresult = Array.isArray(fruits); Try it Yourself » Check if another datatype is an array: lettext ="W3Schools"; letresult = Array.isArray(text); ...
Check if the arrays don't have the same length and if the condition is met, return false. Check if each element in the first array is not equal to the element at the same index in the second array. If the condition is met, return false, otherwise, return true. ...
function oddArray(arr) { let result = []; function helperRecursiveFn(arr) { if(arr.length === 0) { return; // 1 } else if(arr[0] % 2 !== 0) { result.push(arr[0]); // 2 } helperRecursiveFn(arr.slice(1)); // 3 ...
function bubbleSort(array) { const len = array.length if (len < 2) return array for (...