尾递归优化（tail recursion optimization）或者更广义的尾调用优化（tail call optimization）不是没有代价...
但是才疏学浅,有点看不懂,所以把这块知识先空着,待我什么参透在来补上。 http://it.deepinmind.com/jvm/2014/04/16/tail-call-optimization-and-java.html 有兴趣的人可以看看,或者在找些别的资料。小弟,先行告退。
This potential problem can be averted by leveraging tail-recursion optimization. 2.2. Tail Recursion Versus Head Recursion We refer to a recursive function astail-recursionwhen the recursive call is the last thing that function executes.Otherwise, it’s known ashead-recursion. Our implementation above...
触发递归 因此,我们可以这样设计TailCall函数接口: @FunctionalInterfacepublicinterfaceTailCall<T>{TailCall<T>apply();defaultbooleanisComplete(){returnfalse;}defaultTresult(){thrownewError("not implemented");}defaultTinvoke(){returnStream.iterate(this,TailCall::apply).filter(TailCall::isComplete).findFirs...
simple tail call optimization for Java enables infinitely deeptail recursive callswithout throwing aStackOverflowError no transitive dependencies Install add the jitpack repository <repositories> ... <repository> <id>jitpack.io</id> <url>https://jitpack.io</url> </repository> ... </repositories>...
NOTE: This is not a true tail-recursion(尾递归) optimization. 1.2.1 From Recursive To Iterative For the second optimization, we switch from a recursive implementation to an iterative one. Recursive algorithms often have a bad reputation(坏名声) with developers, especially on embedded systems(嵌入...
static List<Integer> calcPrimesUpTo(final int maxValue) { // initially mark all values as potential prime number final boolean[] isPotentiallyPrime = new boolean[maxValue+1]; Arrays.fill(isPotentiallyPrime, true); // run through all numbers starting at 2, optimization only up to half for...
作为 ES2015 (又名 ES6) 标准的一部分,有一个优化用来解决这个问题。它被称作尾调用优化proper tail calls optimization(PTC)。当递归函数做的***一件事是调用自己并返回结果的时候,它使得浏览器删除或者忽略堆栈帧。实际上,这个优化对于相互递归函数也是有效的,但是为了简单起见,我们还是来看单一递归函数。
首先我们从一个小的例子说起：public static void main(String[] args) { // Some implementation here } main方法接受一个字符串数组作为参数并且什么都不返回。如果所有的方法都像main方法一样简单是非常nice的，但是实际上，main方法的方法签名实际上可读性很差。让我们看一下下面的例子：public void setTitle...
As a further optimization, notice that the left task need not even exist. Instead of creating a new one, we can continue using the original task, and add a pending count for each fork. Additionally, because no task in this tree implements an #onCompletion(CountedCompleter) method, tryComplet...