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Solutions to problems on HackerRank. Check out HackerRank's new format here If you are interested in helping or have a solution in a different language feel free to make a pull request. Algorithms Warmup Implementation Strings Sorting Search Graph Theory Greedy Dynamic Programming Constructive ...
Source File: soln.java From HackerRank-solutions with MIT License 5 votes public static void main(String[] args) { HashMap<Integer, Integer> map = new HashMap<>(); ArrayDeque<Integer> deque = new ArrayDeque<>(); Scanner scan = new Scanner(System.in); int n = scan.nextInt(); int...
HackerRank in a String! Java JS C# O(n) O(1) Easy 20 Pangrams Java C# O(n) O(1) Easy 20 Weighted Uniform Strings Java C# O(n) O(n) Easy 20 Separate the Numbers Java C# O(n) O(n) Easy 20 Funny String Java C# O(n) O(n) Easy 25 Gemstones Java C# O(n...
Here I upload my HackerRank Java solutions. java all hackerrank-solutions java-hackerrank-solution java-strings java-stdin java-substring hackerrank-java-solutions Updated Nov 22, 2020 Java anishLearnsToCode / hackerrank-java Star 2 Code Issues Pull requests Java ☕ Domain on HackerRank - ...
N/A Two Strings Are Anagrams.java Easy [] Java 209 N/A Two Sum II - Input array is sorted.java Medium [Array, Binary Search, Two Pointers] Java 210 N/A [HackerRank]. Change to Anagram.java Easy [String] Java 211 N/A Implement Queue using Stacks.java Easy [Design, Stack] Java 21...
N/A Two Strings Are Anagrams.java Easy [] Java 209 N/A Two Sum II - Input array is sorted.java Medium [Array, Binary Search, Two Pointers] Java 210 N/A [HackerRank]. Change to Anagram.java Easy [String] Java 211 N/A Implement Queue using Stacks.java Easy [Design, Stack] Java 21...
A regular expressions, by definition, is a pattern that describes a set of strings. They are used in substring search when the pattern to be found is not completely specified. For example we might want to search for a substring in a genomic sequence that stretches 5 bases, starting with ...
However, this can be bypassed using map = Object.create(null). The keys of an Object are Strings, where they can be any value for a Map. You can get the size of a Map easily while you have to manually keep track of size for an Object....
HackerRank Codility InterviewCake InterviewBit Mock interviewers from big companies Once you're closer to the interview Cracking The Coding Interview Set 2 (videos): Cracking The Code Interview Cracking the Coding Interview - Fullstack Speaker Series Ask Me Anything: Gayle Laakmann McDowell ...