publicclassStringNumberEquality{publicstaticvoidmain(String[]args){StringstrNumber="100";intnumber=100;// 使用 == 比较booleanisEqualUsingEqual=(strNumber==String.valueOf(number));System.out.println("使用 == 比较: "+isEqualUsingEqual);// 输出 false// 使用 equals 方法比较booleanisEqualUsingEqual...
Ref:http://stackoverflow.com/questions/1102891/how-to-check-a-string-is-a-numeric-type-in-java 方法1: 先把string 转换成 char 数组,然后判断每个 char 是否是 数字。 publicbooleanisNumeric(String str) {char[] cs =str.toCharArray();if( !str)returnfalse;for(Char a : cs) {if( !Character....
public static boolean isNumeric3(String str){final String number = "0123456789";for(int i = 0;i < number.length; i ++){if(number.indexOf(str.charAt(i)) == -1){return false;}}return true;}6、捕获NumberFormatException异常public static boolean isNumeric00(String str)...
public static boolean isNumeric3(String str){ final String number = "0123456789"; for(int i = 0;i < number.length; i ++) { if(number.indexOf(str.charAt(i)) == -1) { return false; } } return true;} 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 6、捕获NumberForma...
final String number = "0123456789"; for(int i = 0;i < number.length; i ++) { if(number.indexOf(str.charAt(i)) == -1) { return false; } } return true; } 6、捕获NumberFormatException异常 public static boolean isNumeric00(String str) ...
if (number.indexOf(str.charAt(i)) == -1) { return false;} } return true;} 6. 捕获NumberFormatException异常 此方法尝试将字符串解析为整数。解析失败时捕获异常，返回false。成功解析则返回true。java public static boolean isNumeric00(String str) { try { Integer.parseInt(str);return ...
String contains a creatable number! NumberUtils.isDigits() 该NumberUtils.isDigits()方法检查字符串是否仅包含Unicode数字。如果String包含前导符号或小数点,则该方法将返回false: String string = "25"; if (NumberUtils.isDigits(string)) { System.out.println("String is numeric!"); } else { System.out....
System.out.println("The string is not a valid number."); } 2. 将数字转换为字符串 你也可以将数字转换为字符串,然后与另一个字符串进行比较。 示例 java String strNumber = "123"; int number = 123; // 将数字转换为字符串 String convertedString = String.valueOf(number); ...
isCreatable("") ;返回 false更多信息：https ://www.baeldung.com/java-check-string-number ...
public class Numeric { public static void main(String[] args) { String string = "12345.15"; boolean numeric = true; try { Double num = Double.parseDouble(string); } catch (NumberFormatException e) { numeric = false; } if(numeric) System.out.println(string + " is a number"); else ...