步骤4:编写一个测试类来验证接口是否为函数式接口 // 编写一个测试类publicclassMain{publicstaticvoidmain(String[]args){MyInterfacemyInterface=()->System.out.println("Lambda expression implementing method1");// 如果接口仅包含一个抽象方法,则可以使用Lambda表达式来实现}} 1. 2. 3. 4. 5. 6. 7. ...
1 常规错误解决 can not infer arguments 泛型参数不匹配,经排查,定义的是String类型,传入的是Int类型,导致报错 Could not retrieve connection info from pool 报这个问题,是因为连接池溢出。 如果想从根上解决这个问题,需要运行完关闭连接池即可。 preparement.close(); conn.close(); is not a functional inter...
@FunctionalInterface public interface IRunnable { public abstract String run(); } 结果: alibaba:打印出来了预期值alibaba bilibli 打印返回竟然依旧是:bilibli 目前看达到预期: 此处有些疑惑不解,java@FunctionalInterface interface 和kotlin fun interface虽然有所同,但是kotlin用@FunctionalInterface interface也依旧...
AI代码解释 packagecom.sjh.test.java8.functionInterface;importjava.util.Arrays;importjava.util.List;importjava.util.function.Predicate;publicclassFunctionInterfaceTest{publicstaticvoidmain(String args[]){List<Integer>list=Arrays.asList(1,2,3,4,5,6,7,8,9);// Predicate<Integer> predicate = n ->...
public static void main(String[] args) { // 1.使用匿名内部类的方式 MyFunctionInterface myFunctionInterface = new MyFunctionInterface() { @Override public void show() { System.out.println("Hello 1"); } }; test(myFunctionInterface); ...
Integer value1 = nameMap.computeIfAbsent("name", String::length); Function没有指明参数和返回值的类型,如果需要传入特定的参数,则可以使用IntFunction, LongFunction, DoubleFunction: @FunctionalInterface public interface IntFunction<R> { /** * Applies this function to the given argument. * * @param...
publicListgetEngineersByJobAndAge(List<Enginner>enginnerList,String job,int age){List targetEngineerList=newArrayList();for(Enginner enginner:enginnerList){if(job.equals(enginner.getJob())&&enginner.getAge()>age){targetEngineerList.add(enginner);}}returntargetEngineerList;} ...
// a common interface public interface Common { void f(); void g(); } @FunctionalInterface public interface MyFunction<T, R> { R convert(T); } public class Test { public static void main(String[] args){ // create a instance of common interface ...
@FunctionalInterfaceinterface RejectPolicy<T> {void reject(BlockingQueue<T> queue, T task);}@Slf4jpublic class CustomThreadPool {public static void main(String[] args) {ThreadPool threadPool = new ThreadPool(1, 1000, TimeUnit.MILLISECONDS, 1,(queue,task)->{// queue.getTask();//死等//...
The type is an interface type and not an annotation type, enum, or class. The annotated type satisfies the requirements of a functional interface. However, the compiler will treat any interface meeting the definition of a functional interface as a functional interface regardless of whether or not...