publicclassFindCharacterInString{publicstaticvoidmain(String[]args){Stringstr="Hello, World!";// 定义字符串charch='o';// 定义要查找的字符intindex=str.indexOf(ch);// 使用indexOf()查找字符if(index!=-1){System.out.println("字符 '"+ch+"' 在字符串中的位置是:"+index);}else{System.out....
publicclassMain{publicstaticvoidmain(String[]args){Stringstr="Hello";// 定义字符串chartargetChar='o';// 定义目标字符// 查找目标字符在字符串中出现的位置intindex=str.indexOf(targetChar);// 输出查找结果System.out.println("Character '"+targetChar+"' is found at index: "+index);}} 1. 2....
public static void main(String[] args) { String words = “today,monday,sunday”; System.out.println(“原始字符串是'”+words+”‘”); System.out.println(“indexOf(\”day\”)结果:”+words.indexOf(“day”)); System.out.println(“indexOf(\”day\”,5)结果:”+words.indexOf(“day”,5...
char ch = "棋哥".charAt(0); /***将其他数据类型转换为字符串类型方法1***/ String strb1 = String.valueOf(bool); //将布尔类型转换为字符串类型 String stri1 = String.valueOf(integer); //将整形转换为字符串类型 String strl1 = String.valueOf(LongInt); //将长整型转换为字符串类型 String...
如果需要频繁使用正则表达式来检查,那么我们可以使用String类的matches()方法。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 publicclassMain{publicstaticvoidmain(String[]args){String str="Hello, World!";String regex=".*World.*";boolean isMatch=str.matches(regex);System.out.println(isMatch);/...
String str= "abcdefgABCD中华人民共和国"; String kw1= "中华"; String kw2= "哈哈"; System.out.println(str.contains(kw1)? "str中【有】kw1的元素" : "str中【没有】kw1的元素");//str中【有】kw1的元素System.out.println(str.contains(kw2) ? "str中【有】kw2的元素" : "str中【没有】kw...
实际上，String的contains方法是通过调用indexOf方法来判断的，源码如下：public boolean contains(Char...
int FindIndex(string value, char item) => FindIndex(value, item, 0);int FindIndex(string value, char item, int startAt) => startAt >= value.length ? -1 : value[startAt] == item ? startAt : FindIndex(value, item, startAt + 1); 您可以从字符串的末尾进行检查。 int ...
String differentChars = findUniqueCharacters(str1, str2);System.out.println("不相同的 " + differentChars);}public static String findCommonCharacters(String str1, String str2) {StringBuilder common = new StringBuilder();for (char c : str1.toCharArray()) {if (str2.contains(String.valueOf(c)...
* Find all duplicate characters in a String and print each of them. */ public static void printDuplicateCharacters(String word) { char[] characters = word.toCharArray(); // build HashMap with character and number of times they appear in String ...