length();//长度 if(n==0)return s;//长度为零,直接返回 boolean[][] dp = new boolean[n][n];//二维dp数组 String res = "" + s.charAt(0);//返回值初始为第一个字符 //第一个循环,因为动态转移方程中i+1要在i之前推出,所以i应该从后往前循环 for(int i = n-1; i>=0; i--){ dp...
Time Complexity: O(m*n). m = s1.length(). n = s2.length(). Space: O(m*n). AC Java: 1 class Solution { 2 public boolean isInterleave(String s1, String s2, String s3) { 3 int m = s1.length(); 4 int n = s2.length(); 5 if(m+n != s3.length()){ 6 return false; ...
//Time Complexity: O(N) //Space Complexity: O(M)(此处M为26) public boolean isAnagram(String s, String t) { if (s.length() != t.length()) { return false; } int[] table = new int[26]; //先遍历s,对应索引位置++ for (int i = 0; i < s.length(); i++) { table[s.ch...
function removeDuplicateChar(str){ if (!str || str.length < 2 || typeof str != "string") { return; }; let charArr = [],res = []; for(let i = 0; i < str.length; i++){ let c = str[i]; if(charArr[c]){ charArr[c]++; } else{ charArr[c] = 1; } } for(let...
两个string的末位相加放到string builder尾部. Time Complexity: O(n). n是较长string的length. Space: O(n). AC Java: 1publicclassSolution {2publicString addStrings(String num1, String num2) {3StringBuilder sb =newStringBuilder();4intcarry = 0;5inti = num1.length()-1;6intj = num2.length...
6. String / StringBuilder 1. Definition -> String str = new String(); 2. size -> int length();// TC: O(1) 3. convert to char Array -> toCharArray(); // TC: O(n) 4. value for specific index -> charAt(int index); // TC: O(1) ...
class Main { public static void main(String[] args){ String message = "Hello"; for (int i = 0; i<message.length(); i++){ System.out.print(message.charAt(i+1)); } } }"Hello" A runtime exception is thrown. The code does not compile. "ello"...
cannot be converted to String,so it must be toString}} 18 / 18个通过测试用例,执行用时 :1 ms, 在所有Java提交中击败了98.02%的用户 内存消耗:37 MB
@AerospikeRecord(namespace="test", set="people") public class Person { @AerospikeKey private String ssn; @AerospikeBin(name="frstNme") private String firstName; @AerospikeBin(name="lstNme") private String lastName; private int age; private Date dob; public String getSsn() { return ssn;...
publicclassUniqueCharChecker{publicstaticbooleanbruteForceCheck(String str){char[] chars = str.toUpperCase().toCharArray();for(inti=0; i < chars.length; i++) {for(intj=i +1; j < chars.length; j++) {if(chars[i] == chars[j]) {returnfalse; } } }returntrue; } } ...