* the response with the {@link ResponseExtractor}. * @param url the fully-expanded URL to connect to * @param method the HTTP method to execute (GET, POST, etc.) * @param requestCallback object that prepares the request (can be {@code null}) * @param responseExtractor object that ex...
importjava.io.BufferedReader;importjava.io.InputStreamReader;importjava.io.OutputStream;importjava.net.HttpURLConnection;importjava.net.URL;publicclassPostRequestExample{publicstaticvoidmain(String[]args){try{// 创建URL对象URLurl=newURL("// 创建HttpURLConnection对象HttpURLConnectionconnection=(HttpURLConn...
*@paramjson json格式字符串 *@paramcontentType 这里用 "application/json" *@return*/publicstaticString post(String url, String json, String contentType) { HttpClientBuilder httpClientBuilder=HttpClientBuilder.create();//HttpClientCloseableHttpClient client =httpClientBuilder.build(); client=(CloseableHttpCli...
httpResponse= HttpRequest.post(url)//url.headerMap(heads,false)//请求头设置.body(json.toJSONString())//json参数.timeout(5 * 60 * 1000)//超时.execute();//请求log.info("获取返回服务器的状态码:--- " +httpResponse.getStatus() );if(httpResponse.getStatus() == 200){//成功后响应数据...
import java.io.OutputStream; import java.net.HttpURLConnection; import java.net.URL; public class PostJsonExample { public static void main(String[] args) { try { // 创建一个表示JSON数据的字符串 String jsonInputString = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}...
sendPost(url,""); System.out.println("返回参数"+resp); } @Test void post() { //post 方式 传递参数为json User user=new User("javaNice",666); String paramsMap = JSON.toJSONString(user); System.out.println("传递参数"+paramsMap); String resp = HttpRequestUtil.sendPost("http://...
第Java中POST、GET、@RequestBody和@RequestParam区别详析目录@RequestParam@RequestBody后端解析json数据POST请求时总结参考: @RequestParam 注解@RequestParam接收的参数是来自HTTP请求体或请求url的QueryString中。 RequestParam可以接受简单类型的属性,也可以接受对象类型。 @RequestParam有三个配置参数: required表示是否必须,...
at com.aliyun.oss.common.comm.DefaultServiceClient.sendRequestCore(DefaultServiceClient.java:113) ... 9 more 解决方法 您可以使用ossutil工具快速定位错误原因并解决问题。 报错SignatureDoesNotMatch 错误原因1 AccessKey ID和AccessKey Secret不一致。
String postResult = HttpUtil.doPost(url, json.toJSONString()); System.out.println(postResult); url = "http://localhost:8082/api/test/testSendForm"; Map<String,String> map = new HashMap<>(); map.put("name", "测试表单请求"); String formResult = HttpUtil.doPostForm(url, map); Sys...
"admin",password:"123456",};constencryptedBody=AesUtils.encrypt(JSON.stringify(requestBody),"...