打算用 Scanner 逐行扫描进来,结果报错 “java.util.nosuchelementexception:no line found”. 在网上查,说是已经没有下一行,但是我已经进行了scan.hasNext()检验。然后用 VScode 打开看到编码方式是 UTF-8 with BOM,然后看文档发现 Scanner 有Scanner(File file, String charsetName)的构造器(传送门)。然后搜索文档...
ScannerDemo.java 文件代码: importjava.util.Scanner;publicclassScannerDemo{publicstaticvoidmain(String[]args){Scannerscan=newScanner(System.in);//从键盘接收数据//next方式接收字符串System.out.println("next方式接收:");//判断是否还有输入if(scan.hasNext()){Stringstr1=scan.next();System.out.println(...
下面是一个示例代码,展示了如何使用异常链来处理多个异常: importjava.io.File;importjava.io.FileNotFoundException;importjava.util.Scanner;publicclassFileExample{publicstaticvoidmain(String[]args){try{Filefile=newFile("myfile.txt");Scannerscanner=newScanner(file);while(scanner.hasNextLine()){Stringline=...
三、Scanner默认使用空格作为分割符来分隔文本,但允许你指定新的分隔符 使用默认的空格分隔符: public static void main(String[] args) throws FileNotFoundException { Scanner s = new Scanner(“123 asdf sd 45 789 sdf asdfl,sdf.sdfl,asdf ……asdfkl las”); // s.useDelimiter(” |,|\\.”); w...
并指定字符编码类型publicScanner(Filesource,StringcharsetName)throwsFileNotFoundException{}// 读取路径...
publicstaticvoidmain(String[]args)throws FileNotFoundException{Scanner s=newScanner("123 456 789");while(s.hasNext()){System.out.println(s.next());}}//输入结果就是123456789 二,从文件扫描读入 Scanner的构造器支持多种方式,构建Scanner的对象很方便,可以从字符串(Readable)、输入流、文件等等来直接构建...
(3)Scanner默认使用空格作为分割符来分隔文本,但允许你指定新的分隔符 使用默认的空格分隔符: publicstaticvoidmain(String[] args)throwsFileNotFoundException {Scanners=newScanner("123 asdf sd 45 789 sdf asdfl,sdf.sdfl,asdf ...asdfkl las");// s.useDelimiter(" |,|\\.");while(s.hasNext()) {...
io.FileNotFoundException; import java.util.Scanner; public class ReadFileExample { public static void main(String[] args) { File file = new File("yourfile.txt"); // 确保文件名和路径正确 try { Scanner scanner = new Scanner(file); while (scanner.hasNextLine()) { String line = scanner....
scanner.nextInt(); The API reads the integer token available next. In this case, if the next token is an integer and there is a line separator after the integer, always remember thatnextInt()will not consume the line separator. Instead, the position of the scanner will be the line separ...
When a scanner throws an InputMismatchException, the scanner will not pass the token that caused the exception, so that it may be retrieved or skipped via some other method. Depending upon the type of delimiting pattern, empty tokens may be returned. For example, the pattern "\\s+" will...