This Java tutorial taught us to round off a given floating point number to 2 decimal points using different techniques. We learned to use the Decimal class (recommended),Math,PrecisionandDecimalFormatclasses. As a best practice, always use theDecimalclass with rounding mode set toHALF_EVEN. Happy Learning !! Sourcecode on Github
One way to multiply numbers and round the result to two decimal places is by using theBigDecimalclass provided by Java. TheBigDecimalclass allows precise decimal arithmetic and provides methods to round the result to a specified number of decimal places. Here’s an example code snippet that demon...
select cast(round(cast(a as float)/b,2) as decimal(10,2)) from sysibm.sysdummy1; 先使用cast转a为float,然后运算,再使用round四舍五入取2位小数,然后使用cast转换为decimal(10,2)型。 哎。。。可怜的db2啊。 下边贴一个关于db2小数位的英文文献供参考: Problem You are receiving a SQL0419N mess...
public final static int ROUND_FLOOR:舍入模式向负无穷大舍入。 如果BigDecimal为正数,则按照ROUND_DOWN进行ROUND_DOWN; 如果为负,则按照ROUND_UP方式行事。 请注意,此舍入模式不会增加计算值 public final static int ROUND_HALF_DOWN:舍入模式向“最近邻居”舍入,除非两个邻居等距,在这种情况下向下舍入。
JAVA除法保留小数点后两位的两种方法 Java Math的 floor,round和ceil的总结 2015-05-13 14:12 −floor 返回不大于的最大整数 round 则是4舍5入的计算,入的时候是到大于它的整数round方法,它表示“四舍五入”,算法为Math.floor(x+0.5),即将原来的数字加上0.5后再向下取整,所以,Math.round(11.5)的结果为12...
java中对BigDecimal比较大小一般用的是bigdemical的compareTo方法 代码语言:javascript 代码运行次数:0 运行 AI代码解释 int a=bigdemical.compareTo(bigdemical2) 返回结果分析: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 a=-1,表示bigdemical小于bigdemical2; ...
System.out.println(decimal1.divide(decimal2,BigDecimal.ROUND_CEILING)); 6.8 2.2 10.35 1.956521739130435 double转BigDecimal运算 floatf1=4.5f; floatf2=2.3f; BigDecimald1=newBigDecimal(f1 +""); BigDecimald2=newBigDecimal(f2 +""); System.out.println(d1.add(d2)); ...
Decimal128.clampAndRound(...) int diff = -initialValue.scale() - MAX_EXPONENT; if (initialValue.unscaledValue().equals(BIG_INT_ZERO)) { value = new BigDecimal(initialValue.unscaledValue(), -MAX_EXPONENT); } else if (diff + initialValue.precision() > 34) { throw new NumberFormatException(...
To rounddoubles tondecimal places, we can write ahelper method: private static double round(double value, int places) { if (places < 0) throw new IllegalArgumentException(); BigDecimal bd = new BigDecimal(Double.toString(value)); bd = bd.setScale(places, RoundingMode.HALF_UP); ...
BigDecimal格式化保留2为小数,不足则补0: publicclassNumberFormat{ publicstaticvoidmain(String[] s){ System.out.println(formatToNumber(newBigDecimal("3.435"))); System.out.println(formatToNumber(newBigDecimal(0))); System.out.println(formatTo...