Reverse a linked list from positionmton. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL,m= 2 andn= 4, return1->4->3->2->5->NULL. Note: Givenm,nsatisfy the following condition: 1≤m≤n≤ length of list. 将链表m-n之间的节点反转。 而且已经规定了...
* }*/classSolution {publicListNode reverseList(ListNode head) { ListNode first=head; ListNode reverseHead=null;//建立一个新的节点用来存放结果while(first !=null) {//遍历输入链表,开始处理每一个节点ListNode second = first.next;//先处理第一个节点first,所以需要一个指针来存储first的后继first.next ...
Reverse Linked List II Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ length of ...
publicclassSolution{publicListNodeReverseList(ListNode head){if(head==null)returnnull;//head为当前节点,如果当前节点为空的话,那就什么也不做,直接返回null;ListNode pre=null;ListNode nextnode=null;while(head!=null){nextnode=head.next;head.next=pre;pre=head;head=nextnode;}returnpre;}} Reverse Lin...
Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 既然问了能否iteratively or recursively, 那就both把. iterative 解法: 总结就是得到下一个节点,更改当前节点指向,将指针往下移动,直到过完整个linked...
public ListNode reverseList(ListNode head) { if (head == null || head.next == null){ return head; } ListNode p = reverseList(head.next); //重点 head.next.next = head; head.next = null; return p; } 总结 三种解法中其实利用栈来反转是最简单的,其次是迭代,最难的是递归,递归可以想成...
In this tutorial, we implemented two algorithms to reverse a linked list. As always, the source code for the article is available over on GitHub.Baeldung Pro comes with both absolutely No-Ads as well as finally with Dark Mode, for a clean learning experience: >> Explore a clean Baeldung...
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
链表是一种常见的数据结构,在算法和面试题中经常会遇到。掌握链表的基本操作对于提高编程能力和解决实际问题非常有帮助。 参考资料 [LeetCode: Reverse Linked List]( [GeeksforGeeks: Reverse a Linked List]( “代码示例来源于LeetCode官方题解。”
How to reverse a Singly Linked List in Java https://www.youtube.com/playlist?list=PL6Zs6LgrJj3tDXv8a_elC6eT_4R5gfX4d 讲得比国内的老师清楚