compile(REGEX); Matcher m = p.matcher(INPUT); // 获取matcher 对象 int count = 0; while(m.find()) { count++; System.out.println("Match number "+count); System.out.println("start(): "+m.start()); System.out.println("end(): "+m.end()); } } }...
{privatestaticfinalString REGEX = "\\bcat\\b";privatestaticfinalString INPUT = "cat cat cat cattie cat";publicstaticvoidmain( String args[] ){ Pattern p=Pattern.compile(REGEX); Matcher m= p.matcher(INPUT);//获取 matcher 对象intcount = 0;while(m.find()) { count++; System.out.println...
select sex,avg(math),count(*) from stu where math >70 group by sex having count(*)>2; 1.
int count = 0; String regEx = "[\\u4e00-\\u9fa5]"; String str = "中文fdas "; Pattern p = Pattern.compile(regEx); Matcher m = p.matcher(str); while (m.find()) { count = count + 1; System.out.println(m.groupCount()); System.out.println(m.group()); } System.out.println...
Group zero denotes the entire pattern by convention. It is not included in this count. Any non-negative integer smaller than or equal to the value returned by this method is guaranteed to be a valid group index for this matcher. Java documentation forjava.util.regex.Matcher.groupCount(). ...
Group zero denotes the entire pattern by convention. It is not included in this count. Any non-negative integer smaller than or equal to the value returned by this method is guaranteed to be a valid group index for this matcher. Java documentation for java.util.regex.MatchResult.groupCou...
mat.group(1) 输出为 000 mat.group(2) 输出为 df 如果没有括号会有异常。这就是() 的作用。 如何没有() 可以这样写: publicstaticvoidmain(String []args){ String regEx= "count\\d+"; String s= "count000dfdfsdff1"; Pattern pat=Pattern.compile(regEx); ...
Pattern p = Pattern.compile(REGEX); Matcher m = p.matcher(INPUT); // 获取 matcher 对象 int count = 0; while(m.find()) { count++; System.out.println("Match number "+count); System.out.println("start(): "+m.start()); System.out.println("end(): "+m.end()); ...
...具体来说: 首先,导入了java.util.regex.Matcher和java.util.regex.Pattern这两个类,它们是Java中处理正则表达式的工具类。...如果find方法返回true(即找到了匹配的子字符串),则使用matcher对象的group方法获取第一个匹配的子字符串,并返回该子字符串。...这个正则表达式将匹配以"W"开始,后面跟着一个或多...
(i+":"+matcher.group(i)); } } List<String> getMatchers(String regex, String source){ Pattern pattern = Pattern.compile(regex); Matcher matcher = pattern.matcher(source); List<String> list = new ArrayList<>(); while (matcher.find()) { list.add(matcher.group()); } return list; }...