4. Reading a File Line by Line usingFileReader[Legacy] Till Java 7, we could read a file usingFileReaderin various ways. This has been mentioned for reference only, and shall not be used in Java 8 or later, as it provides no additional benefit for this usecase. Filefile=newFile("c:/...
from:http://www.mkyong.com/java8/java-8-stream-read-a-file-line-by-line/ In Java 8, you can useFiles.linesto read file asStream. c://lines.txt – A simple text file for testing line1 line2 line3 line4 line5 Copy 1. Java 8 Read File + Stream TestReadFile.java packagecom.mkyo...
String line = linReader.nextLine(); System.out.println(line); } linReader.close(); } public static void main(String args[]) throws FileNotFoundException { new readByLine(); } } 输出如下 #12楼 使用Java 8 读取文件 package com.java.java8; import java.nio.file.Files; import java.nio....
private static final String readTextByLine(Context context, int resId) { StringBuilder body = new StringBuilder(); InputStream is = null; InputStreamReader isr = null; BufferedReader br = null; try { //resId写在openRawResource();的参数列表 is = context.getResources().openRawResource(R.raw...
1. Read File Line by Line using BufferedReader In this example, we have a text file named samplefile.txt, and we will read contents of this file, line by line, using BufferedReader class. samplefile.txt This is first line. This is second line. ...
本文翻译自How to read a file line by line in Java 有时我们想逐行读取一个文件来处理内容。 一个很好的例子是逐行读取CSV文件,然后将其用逗号(,)分成多列。 在Java中,当您需要逐行读取文件时,有多种选项可供选择。 1.Scanner Scanner类提供了用Java逐行读取文件的最简单方法。 我们可以使用Scanner类打开文...
import java.io.IOException;import java.nio.file.Files;import java.nio.file.Paths;// somewhere in your codeString content =new String(Files.readAllBytes(Paths.get(fileName))); To read a text file line by line into aListof typeStringstructure you can use the following example. ...
In Python, we read file line by line using different approaches based on clean syntax, ability to read large files, and memory efficiency.
void testReadFile1() throws IOException { //文件内容：Hello World|Hello Zimug String fileName = "D:\\data\\test\\newFile4.txt";try (Scanner sc = new Scanner(new FileReader(fileName))) { while (sc.hasNextLine()) { //按行读取字符串 String line = sc.nextLine();System.out.println...
try(BufferedReader br=newBufferedReader(newFileReader(file))){String line;while((line=br.readLine())!=null){// process the line.}} You can read the data faster if you assume there is no character encoding. e.g. ASCII-7 but it won't make much difference. It is highly likely that wh...