} System.out.print("Sum of digits of number "+tempNum+" is "+total); } } Output: Enter a Number : 5385 Sum of digits of number 5385 is 21 That’s all about Java program to add digits of number.
Output: The program prints the sum of the digits. Solution 2: Sum of Digits using Recursion Code: importjava.util.Scanner;publicclassRecursiveSumOfDigits{//Recursive method to calculatesumof digits public staticintcalculateSum(intnumber){//Base case:If numberis0,return0if(number==0){return0;}...
Input an intger: 25 The sum of the digits is: 7 Flowchart: For more Practice: Solve these Related Problems: Find the sum of digits using recursion. Modify the program to compute the product of digits instead. Find the sum of digits for a very large number. Write a program to sum the...
If you have any doubts while solving the 1 to 100 or 1 To N Prime number program leave a comment here. More Java Programs: Addition, Multiplication, Subtraction, Division Java Program Sum of Digits Of A Number To Reverse An Array Insert an Element In Array Linear Search Add Two Matrices ...
* * @param <U> The type of the result of the mapping function * @param mapper a mapping function to apply to the value, if present * @return an {@code Optional} describing the result of applying a mapping * function to the value of this {@code Optional}, if a value is present,...
*/ public class ValueOfDemo { public static void main(String[] args) { // this program requires two // arguments on the command line if (args.length == 2) { // convert strings to numbers float a = (Float.valueOf(args[0])).floatValue(); float b = (Float.valueOf(args[1]))....
// Java program to count the digits of a number// using the recursionimportjava.util.*;publicclassMain{staticintcount=0;publicstaticintcountDigits(intnum){if(num>0){count++;countDigits(num/10);}returncount;}publicstaticvoidmain(String[]args){Scanner X=newScanner(System.in);intnum=0;intres...
9*2= 81 (Square of 9) 8+1 = 9(Sum of digits in square) Java program to check whether given number is Kaprekar number or notpublic class KaprekarNumbers { public static void main(String[] args) { int ctr = 0; int base = (args.length > 0) ? Integer.parseInt(args[0]) : 10;...
using System;publicclassHappyProgram{publicstaticvoidMain(){ Console.WriteLine("Enter a number: ");intYourNumber=Convert.ToInt16(Console.ReadLine());if(YourNumber >10) Console.WriteLine("Your number is greater than ten");if(YourNumber <=10) Console.WriteLine("Your number is ten or smaller"...
int i=461012;System.out.format("The value of i is: %d%n",i); “%d”指定单个变量是十进制整数。“%n”是独立于平台的换行符。输出为: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 The valueofi is:461012 “printf”和“format”方法已重载。每个都有一个版本,其语法如下: ...