if((number&1) == 1){ System.out.println("您输入的是奇数"); }else{ System.out.println("您输入的是偶数"); } } } (编程题)编写一个程序,判断一个整数的奇偶性,如果是奇数,输出1,是偶数输出2 program Exp1(input,output); var n:longint; begin readln(n); if odd(n) then writeln(1) ...
Write a Java program to calculate the sum of all even, odd numbers in a list using streams. Sample Solution:Java Code:import java.util.Arrays; import java.util.List; public class NumberSum { public static void main(String[] args) { List < Integer > numbers = Arrays.asList(1, 2, 3,...
下面是一个描述该程序执行顺序的序列图: ProgramUserProgramUserRepeat until all elements are checkedRun ProgramInitialize arrayLoop through arrayOutput odd number 在上述序列图中,用户运行程序后,程序首先初始化数组,接着循环检查数组中的每个元素,并输出所有发现的奇数,最后完成整个过程。 结论 通过以上的示例,我们...
Write a Java program to print odd numbers from 1 to 99. Prints one number per line. Pictorial Presentation: Sample Solution: Java Code: importjava.util.*;publicclassExercise48{publicstaticvoidmain(String[]args){// Iterate through numbers from 1 to 99for(inti=1;i<100;i++){// Check if ...
This is a Java Program to Calculate the Sum of Odd & Even Numbers. Enter the number of elements you want in array. Now enter all the elements you want in that array. We begin from the first element and check if it is odd or even. Hence we add that number into the required addition...
1 2 3 4 5 6 7 8 9 10 11 12 EnterN: 5 EnterSymbol:* ** ** ** ** * ** ** ** ** More Programs: List of 50 Different Star & Number Pattern Programs Bubble Sort Java Program Selection Sort Java Program Insertion Sort
next() { lock.lock(); try { ++currentEvenValue; new Nap(0.01); // Cause failure faster ++currentEvenValue; return currentEvenValue; } finally { lock.unlock(); } } public static void main(String[] args) { EvenChecker.test(new MutexEvenProducer()); } } /* No odd numbers discovered...
out.println("Provide a number:"); prdnum = oddevn.nextInt(); if (prdnum % 2 == 0) System.out.println("Provided number is even"); else System.out.println("Provided number is odd"); } } Output:This program will check whether a number is even or odd. The user provides the ...
Notified odd :17 Odd Thread :17 Checking odd loop Odd waiting : 18 Notified even:18 Even thread :18 Checking even loop Even waiting: 19 Notified odd :19 Odd Thread :19 Notified even:20 Even thread :20 If you observe output, you should be able to understand above program. Let me try...
Program using interfaces so that the actual structure can be easily swapped to improve performance. Use the -g:none option to the javac compiler. Primitive data wrapper classes (e.g. Integer) are slower than using the primitive data directly. Null out references when they are no longer used...