public ListNode mergeTwoLists(ListNode list1, ListNode list2) { if (list1 == null) return list2; if (list2 == null) return list1; if (list1.val <= list2.val) { list1.next = mergeTwoLists(list1.next,list2); return list1; } else { list2.next = mergeTwoLists(list1,list2....
class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { if (l1 == null){ return l2; } else if (l2 == null){ return l1; } else if (l1.val < l2.val){ l1.next = mergeTwoLists(l1.next, l2); return l1; } else{ l2.next = mergeTwoLists(l1, l2.next); ...
应该通过将前两个列表的节点拼接在一起来创建新列表。 Java解决方案 解决问题的关键是定义一个假冒的头部。然后比较每个列表中的前几个元素。将较小的一个添加到合并列表中。最后,当其中一个为空时,只需将其追加到合并列表中即可,因为它已经排序。 public ListNode mergeTwoLists(ListNode l1, ListNode l2) { ...
//递归法 class Solution { public static ListNode mergeTwoLists(ListNode l1,ListNode l2){ if(l1==null)return l2; if (l2==null)return l1; if(l1.val<l2.val){ l1.next=mergeTwoLists(l1.next,l2); return l1; }else{ l2.next=mergeTwoLists(l1,l2.next); return l2; } } } 算法时间复...
In the above exercise, we define a generic method mergeLists() that takes two lists list1 and list2 as input. The method creates a newly created mergedList from an ArrayList. It iterates up to the maximum length of the two lists using a for loop. In each iteration, it checks if the...
1#Definition for singly-linked list.2#class ListNode:3#def __init__(self, val=0, next=None):4#self.val = val5#self.next = next6classSolution:7defmergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) ->Optional[ListNode]:8ifnotlist1:9returnlist210ifnotlist2:11...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 两个排好序的链表拼接,只要用两个指针遍历链表即可. 可以借助一个helper指针来进行开头的合并。如果有一个遍历完,则直接把另一个链表指针之后的部分全部接...
Write a Java program to merge the two sorted linked lists.Sample Solution:Java Code:import java.util.* public class Solution { public static void main(String[] args) { // Create two sorted linked lists ListNode list1 = new ListNode(1); list1.next = new ListNode(3); list1.next.next ...
if(l2 == null){ return l1; } ListNode mergeHead; if(l1.val < l2.val){ mergeHead = l1; mergeHead.next = mergeTwoLists(l1.next, l2); } else{ mergeHead = l2; mergeHead.next = mergeTwoLists(l1, l2.next); } return mergeHead; } }...
Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 1.解题思路 合并两个有序链表,同样需要构造一个Dummy节点。 1)考虑特殊情况,如果有一个链表为空,则直接返回另一个链接; ...