This is one of the reasons for enterprise Java development. Enterprises that require scalable solutions believe in Java enterprise application development to manage the operational requirements. The programming language is beneficial to enterprises for a broad array of applications like creating an Android ...
c) Java is a platform-dependent programming language d) Java is a platform-independent programming language View Answer 3. Which component is used to compile, debug and execute the java programs? a) JRE b) JIT c) JDK d) JVM View Answer 4. Which one of the following is not a Java fea...
net.*; class networking { public static void main(String[] args) throws MalformedURLException { URL obj = new URL("https://www.sanfoundry.com/javamcq"); System.out.print(obj.getPort()); } } 1 0 garbage value -1 Question 1 of 50 Topic wise Test Quizzes on Java Java tests, quiz...
2 x OCA Certification Tests - mimics the actual Oracle OCA exam in that each of them have 56 MCQ's. You have 2 hours to complete the test and need 65% to pass (ref: Oracle, April 2024). 15 x OCA Practice Quizzes The course now has a total of 248 MCQ's overall; each of wh...
我们整理了Python面试的主要问题清单,分为7个部分: 基本面试问题 OOPS面试问题 基本的Python程序 Python库面试问题 数据分析面试题 选择题(MCQ) 基本的Python面试问题 Q1。Python中的列表和元组有什么区别? LIST TUPLES 列表是可变的,即可以编辑。 元
是MCQA1.0独有的概念,详细信息可以参考[MCQA 1.0](../core-concept/execute-sql/mcqav1.md)。 ```java public SQLExecutorBuilder attachTimeout(Long timeout) @@ -303,28 +303,48 @@ public SQLExecutorBuilder runningCluster(String runningCluster) - **参数**:`runningCluster` - 字符串,表示运行集群...
1. 在移动互联网时代一个APP为了抢占市场,APP推广已经是必须的过程,然而真实用户的获客成本居高不下,在利益的驱动下引来羊毛党、刷量工作室对流量作弊造假利益链,如果只是做了简单根据IP和设备信息来防作弊,很难防住这些职业刷量人,假量造成了数据来源不真实,无法用于分析并支持App推广运营决策,最后也只能感叹“为...
master 分支(9) 标签(99) 管理 管理 master dependabot/npm_and_yarn/ini-1.3.8 jdk.next enableProposedFeature yaohai_dev onChange yaohai_test outline issue-431 v1.9.0 v1.8.0 v1.7.0 v1.6.0 v1.5.0 v1.4.0 v1.3.0 v1.2.0 v1.1.0 v1.0.0 v0.82.0 v0.81.0 v0.80.0 v0.79.2 ...
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int[][]minHashValues, Map<T,boolean[]>bitArray) { intindex=0; for(T element:bitArray.keySet()) { /* * for every element in the bit array */ for(inti=0;i<numHash;i++) { /* * for every hash */ if(set.contains(element)) ...