方式一:循环遍历拼接的方式 public void ListToString() { List<String> list = Arrays.asList("张三", "李四", "王五", "赵六");StringBuilder builder = new StringBuilder();for (int i = 0; i < list.size(); i++) { builder.append(list.get(i));builder.append(",");} String substring...
代码如下: List<String>stringList=Arrays.asList("1.0","2.0","3.0");for(Stringstr:stringList){// 将字符串转换为双精度浮点数doubledoubleValue=Double.parseDouble(str);// 将双精度浮点数添加到新列表中resultList.add(doubleValue);} 1. 2. 3. 4. 5. 6. 7. 在上面的示例中,我们假设输入的字符...
StringlistString="[\"item1\", \"item2\", \"item3\"]";List<String>list=Arrays.asList(listString.substring(1,listString.length()-1).split(", ")); 1. 2. 上述代码中,listString是要转换的String类型的List字符串,通过使用substring()方法去掉字符串的首尾方括号,再使用split()方法将字符串分割...
正式开始 1System.out.println("++++++++++++++++++");2System.out.println("List转字符串");3List<String> list1 =newArrayList<String>();4list1.add("1");5list1.add("2");6list1.add("3");7String ss = String.join(",", list1);8System.out.println(StringUtils.join("",list1));...
String[] strs2 = new String[testList.size()]; for(int i=0;i<testList.size();i++){ strs2[i]=testList.get(i); } for(String s:strs2){ System.out.println(s); } 二:String数据转List 方法一: //准备一个String数组 String[] strs = {"aa","bb","cc"}; ...
First of all, why is the map a HashMap<String, ArrayList<String>> and not a HashMap<String, List<String>>? Is there some reason why the value must be a specific implementation of interface List (ArrayList in this case)? Arrays.asList does not return a java.util.ArrayList, so you ca...
这个使用java8的stream可以很好的解决 List codesInteger = codes.stream().map(Integer::parseInt).c...
string 数字转 list string publicstaticvoidmain(String[]args){List<String>strlist=newArrayList<String>();strlist.add("aaaa");strlist.add("bbbb");String[]strarray=strlist.toArray(newString[0]);System.out.println(strarray);}
有关文档,请参阅here,请注意,您还可以调用此方法,使其填充传递的数组,而不仅仅是使用它来确定要...