使用get(index)方法获取LinkedList中指定索引位置的元素: 复制 String element = linkedList.get(index); 1. 修改元素: 使用set(index, element)方法可以修改LinkedList中指定索引位置的元素: 复制 linkedList.set(index, "newValue"); 1. 删除元素: 使用remove()方法删除LinkedList的第一个元素: 复制 linkedList.rem...
2)All of the operations perform as could be expected for a doubly-linked list. Operations that index into the list will traverse the list from the beginning or the end, whichever is closer to the specified index. 这个告诉我们,linkedList在执行任何操作的时候,都必须先遍历此列表来靠近通过index查找...
因为首先要定位到要移除的元素的位置,然后再执行出队操作,remove最终执行的出队方法是依赖removeAt(final int removeIndex),而removeAt的出队操作是定位到要移除的元素位置后,将takeIndex位置的元素替换掉要移除的元素,就完成了出队操作 。
public void insertAtIndex(E element, int index) { if (index < 0 || index > size()) { throw new IndexOutOfBoundsException("Invalid index"); } Node newNode = new Node(element); if (index == 0) { newNode.next = head; if (head != null) { head.prev = newNode; } head ...
NoSuchElementException − if list is empty.Java LinkedList remove(object) MethodDescriptionThe Java LinkedList remove(int index) method removes the element at the specified position in this list. Shifts any subsequent elements to the left (subtracts one from their indices)....
1、根据下标移除,public E remove(int index) 2、根据内容移除,publicbooleanremove(Object o) 要注意自己调用的remove()方法中的,传入的是int类型还是一个对象。 List 删除元素的逻辑是将目标元素之后的元素往前移一个索引位置,最后一个元素置为 null,同时 size - 1;所以按照从大往小的方向删除不容易出错 ...
a.removeAt( i ); } }for(inti =0; i < a.size(); i++ ) {intexpected = i *2+1; assertTrue("index "+ i +" expected "+ expected, a.get( i ) == expected ); } } 开发者ID:palantir,项目名称:trove-3.0.3,代码行数:23,代码来源:TPrimitiveLinkedListTest.java ...
对List 进行删除操作可能会产生并发问题; 我们通过代码示例演示正确的删除逻辑 package com.ips.list; import java.util.ArrayList; import java.util.Iterator; import java.util.List; import java.util.concurrent.CopyOnWriteArrayList; public class ArrayListRemove { public static void main(String[] args) { Arr...
LinkedList is implemented as a double linked list. The get is pretty clear. O(1) for ArrayList, because ArrayList allow random access by using index. O(n) for LinkedList, because it needs to find the index first. Note: there are different versions of add and remove. LinkedList is ...
public RemoveByFor(List<String> list){ this.list = list; } //错误1:for循环删除ArrayList中的指定值对象,如下写法ArrayList中"bb"只删除了一个,未全部删除 // //原因: //由上述可知,删除指定元素最终用到的方法为fastremove,它的实现原理为位置移动,在此处错误场景中, ...