初始化ListB section 遍历ListA for each element in ListA section 判断元素是否存在于ListB if element exists in ListB section 添加相同元素到结果集合 add element to result set section 输出结果 输出结果集合 代码实现 首先,我们需要初始化两个List,并填充一些数据
next; } catch (IndexOutOfBoundsException e) { checkForComodification(); throw new NoSuchElementException(); } } /** * 移除上一次调用 next() 方法返回的元素 */ public void remove() { if (lastRet < 0) throw new IllegalStateException(); checkForComodification(); try { AbstractList.this...
记录遍历到的当前List中的element,所以在 foreach中操作的对象是指向临时变量的,而不是List中的element实例对象的地址,结果自然就只是修改临时变量的值并没修改List中的element,所以才会出现:foreach增强for循环中修改List中element的值是无效的问题;
importjava.util.ArrayList;importjava.util.List;publicclassFindElementInList{publicstaticvoidmain(String[]args){List<String>list=newArrayList<>();list.add("apple");list.add("banana");list.add("orange");Stringtarget="banana";booleanfound=false;for(Stringelement:list){if(element.equals(target)){f...
}if(!found) { difference.add(element); } } System.out.println("差集为:" + difference); 输出结果为: 差集为:[1, 2] 这种方法的时间复杂度为O(n^2),其中n为两个List的大小之和。当List较大时,性能可能会受到影响。 方法二:使用Java 8的Stream API ...
if (element == toCheckValue) { test = true; break; } } System.out.println("Is " + toCheckValue + " present in the array: " + test); } public static void main(String[] args) { int arr[] = {5, 1, 1, 9, 7, 2, 6, 10}; ...
if (curr == elements.length - 1) { // 数组满了,扩容一倍,把数据拷贝到新数组里。 Object[] temp = new Object[elements.length * 2]; System.arraycopy(elements, 0, temp, 0, elements.length); elements = temp; } elements[curr] = o; ...
List targetElement = driver.findElements(By.xpath("xpath_your_expected_element")); try{ if(targetElement>=1) { if(targetElement.isDisplayed()) { System.out.println("Element is present"); }else{ System.out.println("Element is found, but hidden on the page"); ...
.util.List; public class Main { public static void main(String[] args) { List<String> list = new ArrayList<>(); list.add("apple"); list.add("banana"); list.add("orange"); String element = "banana"; if(list.contains(element)) { System.out.println(element + " is in the list....
Returns the index of the first occurrence of the specified element in this list, or -1 if this list does not contain the element.booleanisEmpty() Returns true if this list contains no elements.Iterator<E>iterator() Returns an iterator over the elements in this list in proper sequence.int...