BigDecimal one =newBigDecimal("1"); returnb.divide(one,scale,BigDecimal.ROUND_HALF_UP).doubleValue(); } /** * 提供精确的类型转换(Float) * @param v 需要被转换的数字 * @return 返回转换结果 */ publicstaticfloatconvertsToFloat(doublev){ BigDecimal b =newBigDecimal(v); returnb.floatValue()...
定义double g= 12.35; 而在计算机中二进制表示可能这是样:定义了一个g=12.34444444444444449, new BigDecimal(g) g还是12.34444444444444449 new BigDecimal(g).setScale(1, BigDecimal.ROUND_HALF_UP); 得到12.3正确的定义方式是使用字符串构造函数:new BigDecimal("12.35").setScale(1, BigDecimal.ROUND_HALF_UP) ...
The floating-point types are float and double, which are conceptually概念 associated with the single-precision 32-bit and double-precision 64-bit format IEEE 754 values and operations as specified指定 in IEEE Standard for Binary Floating-Point Arithmetic, ANSI/IEEE Standard 754-1985 (IEEE, New Yo...
而在Java 中,默认舍入模式为 RoundingMode.HALF_EVEN,即 "Round to nearest, ties to even" 该舍入模式也被称为 "Banker's rounding",在统计学上这种模式可以使累计的误差最小4.手动计算IEEE754值示例以常见的 0.1 和 float 为例: 0.1(10)=0.0001100110011...(2)=(−1)0∗1.100110011...01(2)∗...
publicclassPercentagePrecisionComparison{publicstaticvoidmain(String[]args){double doubleResult=0.1+0.2;BigDecimal bigDecimalResult=newBigDecimal("0.1").add(newBigDecimal("0.2"));System.out.println("Double result: "+doubleResult);System.out.println("BigDecimal result: "+bigDecimalResult);}} ...
You are not changing any numerical "precision." ? 1 2 3 4 5 6 7 8 9 import java.text.*; class Decimals { public static void main(String[] args) { float f = 125.0f; DecimalFormat form = new DecimalFormat("0.00"); System.out.println(form.format(f)); } } [ September 27, 2005...
@Slf4j@RunWith(SpringRunner.class)@SpringBootTest(classes = ReportApplication.class)public class PrecisionTest {//鼓励用BigDecimal解决精度问题@Testpublic void test1() {Double a = 12.0;Double b = 11.9;System.out.println("last result:" + (a - b));System.out.println("===");///we use B...
Most processors take almost same time in processing the operations on float and double but double offers way more precision then float that is why it is best practice to use double when precision is important otherwise you can go with float as it requires half space than double.。
intprecision() このBigDecimalの精度を返します。 BigDecimalremainder(BigDecimal divisor) 値が(this % divisor)であるBigDecimalを返します。 BigDecimalremainder(BigDecimal divisor, MathContext mc) コンテキスト設定に従った丸めを使用して、値が(this % divisor)であるBigDecimalを返します。 BigDeci...
If the precision is less than the number of digits which would appear after the decimal point in the string returned by Float.toString(float) or Double.toString(double) respectively, then the value will be rounded using the round half up algorithm. Otherwise, zeros may be appended to reach ...