下面我们通过一个示例代码来说明getPackageName()方法的用法: importjava.util.ArrayList;publicclassGetPackageNameExample{publicstaticvoidmain(String[]args){ArrayList<String>list=newArrayList<>();Class<?>clazz=list.getClass();StringpackageName=clazz.getPackageName();System.out.println("Package name: "+pa...
通过访问mBase属性,我们可以获取到一个基本的Context对象,然后调用其getPackageName()方法获取当前App的包名。 总结 本文介绍了几种获取当前App包名的方法,包括使用Context的getPackageName()方法、Activity的getPackageName()方法、PackageInfo的applicationInfo属性、ActivityThread的currentPackageName属性以及反射获取Context的m...
jstring PackageName= (jstring)(*env)->CallObjectMethod(env, activity->clazz, midGetPackageName);boolret =false;if( PackageName !=null) {//get UTF8 string & copy to destconstchar* charBuff = (*env)->GetStringUTFChars(env, PackageName, NULL);strncpy(outPackageName, charBuff, length); out...
logger.info("{} ",pk.getName()); } logger.info("共计 {} 个包",packages.length); Package findPackage= Package.getPackage("java.io"); logger.info("查找结果 {}",findPackage.getName()); Package pka= Class.forName("java.lang.Package").getPackage(); pka= Class.forName("org.slf4j.L...
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Package.Name 屬性參考 意見反應 定義命名空間: Java.Lang 組件: Mono.Android.dll 傳回此套件的名稱。C# 複製 public virtual string? Name { [Android.Runtime.Register("getName", "()Ljava/lang/String;", "GetGetNameHandler")] get; }
packagecom.itweb.pojo;publicclassUser{privateString name;privateInteger age;privateAddress address;publicStringgetName(){returnname;}publicvoidsetName(String name){this.name=name;}publicIntegergetAge(){returnage;}publicvoidsetAge(Integer age){this.age=age;}publicAddressgetAddress(){returnaddress;}publ...
sudoaptpurge<package_name> 将<package_name>替换为要卸载的Java软件包的名称。例如,要卸载Oracle Java 8,可以执行以下命令: 代码语言:shell AI代码解释 sudoaptpurge oracle-java8-installer 请根据您的安装情况重复此步骤,并卸载所有相关的Oracle Java软件包。
Namespace: Java.Lang Assembly: Mono.Android.dll Return the name of this package. C# Cóipeáil public virtual string? Name { [Android.Runtime.Register("getName", "()Ljava/lang/String;", "GetGetNameHandler")] get; } Property Value String The fully-qualified name of this package as...
public Class<?> loadClass(String name) throws { String filename = "D:\\WorkSpace\\IDEA\\HelloWorld\\out\\production\\HelloWorld\\xiao\\" + name.split("\\.")[name.split("\\.").length - 1] + ".class"; InputStream is = getClass().getResourceAsStream(filename); if (is == null...