public static void main(String[] args) { double number = 123.456789; System.out.printf("Formatted to two decimal places: %.2f%n", number); } } 运行结果: Formatted to two decimal places: 123.46 说明: %.2f 表示格式化为浮点数并
我们可以使用DecimalFormat类来保留两位小数。 importjava.text.DecimalFormat;publicclassDecimalUtils{publicstaticdoubleroundToTwoDecimalPlaces(doublenumber){DecimalFormatdf=newDecimalFormat("#.00");returnDouble.parseDouble(df.format(number));}} 1. 2. 3. 4. 5. 6. 7. 8. 上面的代码定义了一个DecimalUtil...
首先,我们定义了一个静态方法roundToTwoDecimalPlaces,该方法接受一个double类型的参数number,并返回保留两位小数四舍五入后的结果。 在roundToTwoDecimalPlaces方法中,我们使用了Math.round方法将number乘以100后进行四舍五入,并将结果除以100.0得到保留两位小数四舍五入后的结果。 然后,我们在main方法中定义了一个doubl...
We create a new instance of theDecimalFormat. We pass it a non-localized pattern string. The pattern defines a format for a decimal value with a dot followed by two decimal places. df.applyPattern("#.00"); We specify a new pattern withapplyPattern. This pattern adds zeros to decimal place...
System.out.println(decimal.toString());//输出:9E-14System.out.println(decimal.toPlainString());//输出: 0.00000000000009System.out.println(decimalFormatNumberOfDecimalPlaces2.format(decimal));//输出:0.00Map<String, Object> map =newjava.util.HashMap<>(); ...
使用String.format () 方法,它可以按照指定的格式化字符串来输出数值,比如 “%.1f” 表示保留一位小数。例如: doublenum=3.14159;Stringresult=String.format ("%.1f", num);// result = "3.1" 复制 使用DecimalFormat 类,它可以按照指定的模式来格式化数值,比如 “#.#” 表示保留一位小数。例如: ...
System.out.println("Without fraction part: num = "+ ft.format(num));// this will print it upto 2 decimal placesft =newDecimalFormat("#.##"); System.out.println("Formatted to Give precision: num = "+ ft.format(num));// automatically appends zero to the rightmost part// of decimal...
The result should be rounded to 2 decimal places If and only if it is not an integer. Sample Input 4 + 1 2 –1 2 * 1 2 / 1 2 Sample Output 3 -1 2 0.50 代码语言:javascript 代码运行次数:0 运行 AI代码解释 import java.util.Scanner; public class Main { public static void main(...
Learn toround off numeric values (floats and doubles) to 2 decimal places in Java. Note that we can use the given solutions to round off to any number of places according to requirements. Quick Reference doublenumber=4.56789; // 1. Using Math.round()doublerounded=Math.round(number*100.0)/...
Returns a BigDecimal which is equivalent to this one with the decimal point moved n places to the left. BigDecimalmovePointRight(int n) Returns a BigDecimal which is equivalent to this one with the decimal point moved n places to the right. BigDecimalmultiply(BigDecimal multiplicand) Returns a...