for each element in ListA section 判断元素是否存在于ListB if element exists in ListB section 添加相同元素到结果集合 add element to result set section 输出结果 输出结果集合 代码实现 首先,我们需要初始化两个List,并填充一些数据。假设我们有两个List:listA和listB
"banana","orange");List<String>list2=Arrays.asList("apple","banana");booleanisContained=true;for(Stringelement:list2){if(!list1.contains(element)){isContained=false;break;}}System.out.println("List 1 contains all elements in List
*/publicstaticListforceForRemove(List list,Object element){for(Object item:list){if(item.equals(element)){list.remove(item);}}returnlist;} 异常如下: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 Exceptioninthread"main"java.util.ConcurrentModificationException at java.util.ArrayList$Itr.checkF...
foreach遍历JDK5.0增加的增强for循环,foreach在遍历过程中是通过一个临时变量,记录遍历到的当前List中的element,所以在 foreach中操作的对象是指向临时变量的,而不是List中的element实例对象的地址,结果自然就只是修改临时变量的值并没修改List中的element,所以才会出现:foreach增强for循环中修改List中element的值是无效...
返回差集List。 以下是使用这种方法的代码示例: List<Integer> list1 = Arrays.asList(1, 2, 3, 4, 5); List<Integer> list2 = Arrays.asList(3, 4, 5, 6, 7); List<Integer> difference =newArrayList<>();for(Integer element : list1) {booleanfound =false;for(Integer compareElement : list...
import java.util.List; public class UseListAppMain { public static void main(String[] args) { List myList = new MyArrayList(); for (int i = 0; i < 10; i++) { myList.add("str" + (i % 5)); } System.out.println(); ...
for (T element : elements) result |= c.add(element);//result和c.add(element)按位或运算,然后赋值给result return result; } 四.Java8可通过stream流将3种基本类型数组转为List 如果JDK版本在1.8以上,可以使用流stream来将下列3种数组快速转为List,分别是int[]、long[]、double[],其他数据类型比如short...
list.add(5); System.out.println("***遍历时移除元素***"); Iterator<Integer> iterator = list.iterator();while(iterator.hasNext()) {// iterator.remove()前,必须先执行iterator.next(),将next element的索引+1,否则会出现IllegalStateExceptionInteger num = iterator.next(); System....
public interface List<E> extends Collection<E>An ordered collection (also known as a sequence). The user of this interface has precise control over where in the list each element is inserted. The user can access elements by their integer index (position in the list), and search for ...
System.out.println("栈顶元素:"+ peekElement);// 获取栈中元素的个数intstackSize = stack.getSize(); System.out.println("栈中元素个数:"+ stackSize); } 4. 运行结果 入栈操作:LinkedListStack{list=[A]} 入栈操作:LinkedListStack{list=[A, B]} ...