importjava.io.File;importjava.nio.file.Path;importjava.nio.file.Paths;publicclassGetFilePathWithoutFileName{publicstaticvoidmain(String[]args){// 使用File类获取文件路径Filefile=newFile("C:/test/example.txt");StringfilePath=file.getParent();System.out.println("文件路径不包含文件名:"+filePath);/...
我们可以通过File类的getName()方法获取文件的名称。但是该方法返回的文件名包含路径信息,如/path/to/file.txt。如果我们只需要文件名而不带路径信息,可以使用以下方法: publicstaticStringgetFileNameWithoutPath(StringfilePath){Filefile=newFile(filePath);StringfileName=file.getName();intindex=fileName.lastInde...
importorg.apache.commons.vfs.FileName;//导入方法依赖的package包/类publicstaticStringgetFilename(FileObject fileObject){ FileName fileName = fileObject.getName(); String root = fileName.getRootURI();if(!root.startsWith("file:"))returnfileName.getURI();// nothing we can do about non-normal...
FileName: AmanCV.docx 示例2: // Java program to demonstrate// java.nio.file.Path.getFileName() methodimportjava.io.IOException;importjava.nio.file.Path;importjava.nio.file.Paths;publicclassGFG{publicstaticvoidmain(String[] args)throwsIOException{// create object of PathPath path = Paths.get(...
ftpClient.storeFile(fileName, fis); Log.info("上传文件成功："+fileName+"。文件保存路径："+"/"+filepath+"/"); return bl; } catch (Exception e) { throw e; } finally { if (fis != null) { try { fis.close(); } catch (Exception e) { Log.info(e.getLocalizedMessage()...
Files.exists(path)) { return path; }//w ww . j av a 2 s . c o m // Determine name and extension final String name = path.getFileName().toString(); final int fileTypeIndex = name.lastIndexOf("."); String nameWithoutExtension; String extension; if (fileTypeIndex == -1) { ...
Namespace: Java.IO Assembly: Mono.Android.dll An abstract representation of file and directory pathnames.C# 複製 [Android.Runtime.Register("java/io/File", DoNotGenerateAcw=true)] public class File : Java.Lang.Object, IDisposable, Java.Interop.IJavaPeerable, Java.IO.ISerializable, Java....
Returns an array of abstract pathnames denoting the files and directories in the directory denoted by this abstract pathname that satisfy the specified filter. C# [Android.Runtime.Register("listFiles","(Ljava/io/FilenameFilter;)[Ljava/io/File;","GetListFiles_Ljava_io_FilenameFilter_Handler")]pu...
Arguments after the class file name or the JAR file name are passed to the main() method. Using Source-File Mode to Launch Single-File Source-Code Programs To launch a class declared in a source file, run the java launcher in source-file mode. Entering source-file mode is determined by...
The location of a file on a system can be determined by its path. In PowerShell, there are several ways to get filename from path. Firstly, it's essential to