这段代码首先使用Scanner获取用户输入的字符串和单词,然后调用countOccurrences方法来统计次数,并最终输出结果。 2. 分割字符串 我们可以使用split方法将字符串按空格分割成一个单词数组。 publicstaticintcountOccurrences(StringinputString,StringwordToFind){// 将输入字符串按空格分割成单词数组String[]words=inputString...
index))!=-1){count++;index+=subStr.length();}returncount;}publicstaticvoidmain(String[]args){Stringstr="Java is a programming language, Java is used widely in the software industry.";StringsubStr="Java";intoccurrences=countOccurrences(str,subStr...
StringUtils.countOccurrencesOf("erowoiueoiur","oiur") ==1; StringUtils.countOccurrencesOf("erowoiueoiur","r") ==2;//字符串替换StringinString="a6AazAaa77abaa";StringoldPattern="aa";StringnewPattern="foo";// Simple replaceStrings=StringUtils.replace(inString, oldPattern, newPattern); s.eq...
要实现`countoccurrencesof`方法,我们可以使用 Java 的正则表达式和`Matcher`类。以下是一个简单的示例: ```java import java.util.regex.Matcher; import java.util.regex.Pattern; public class Main { public static void main(String[] args) { String text = "I love Java programming language.Java is a...
publicstaticvoidmain(String[]args){JdkIdGenerator jdkIdGenerator=newJdkIdGenerator();AlternativeJdkIdGenerator alternativeJdkIdGenerator=newAlternativeJdkIdGenerator();SimpleIdGenerator simpleIdGenerator=newSimpleIdGenerator();Instant start;Instant end;int count=1000000;//jdkIdGeneratorstart=Instant.now();fo...
CodePointCount(Int32, Int32) Returns the number of Unicode code points in the specified text range of this String. CompareTo(String) Compares two strings lexicographically. CompareToIgnoreCase(String) Compares two strings lexicographically, ignoring case differences. Concat(String) Concatenates the...
Map<String, String> map =newConcurrentReferenceHashMap<>(8, ConcurrentReferenceHashMap.ReferenceType.WEAK); map.put(key, value); System.out.println(map);//{key=val}key =null; System.gc();//等待一会 确保GC能够过来TimeUnit.SECONDS.sleep(5); ...
{ // Check if the count of a character (after removal) is more than 2 in the string if (text.length() - text.replaceAll(text.charAt(0) + "", "").length() > 2) { ctr++; // Increment the counter if duplicate characters are found more than twice } // Remove all occurrences ...
import java.io.*; import java.util.*; import java.util.concurrent.*; public class WordCounter { String[] wordsIn(String line) { return line.trim().split("(\\s|\\p{Punct})+"); } Long occurrencesCount(Document document, String searchedWord) { long count = 0; for (String line : ...
Allocates a new String so that it represents the sequence of characters currently contained in the character array argument. String(char[] value, int offset, int count) Allocates a new String that contains characters from a subarray of the character array argument. String(int[] codePoin...