importjava.util.ArrayList;importjava.util.List;publicclassCompareLists{publicstaticvoidmain(String[]args){// 创建并初始化第一个 ListList<String>list1=newArrayList<>();list1.add("Apple");list1.add("Banana");list1.add("Cherry");// 创建并初始化第二个 ListList<String>list2=newArrayList<>()...
下面是一个使用Set数据结构判断两个List是否存在重复项的示例代码: importjava.util.ArrayList;importjava.util.HashSet;importjava.util.List;importjava.util.Set;publicclassCompareTwoLists{publicstaticbooleanhasDuplicate(List<Integer>list1,List<Integer>list2){Set<Integer>set1=newHashSet<>(list1);Set<Intege...
因此,如果使用不可变列表,请考虑将它们包装在ArrayList实例中。 static boolean compareListsIgnoringOrder(ArrayList list1, ArrayList list2) { if (list1 == null || list2 == null) return false; if (list1.size() != list2.size()) return false; for (Object o : list1) { list2.remove(o);...
Note that the difference between two lists is equal to a third list which contains either additional elements or missing elements. 1. Comparing Two Lists for Equality 1.1. Sort then Compare The following Java program tests if two given lists are equal. To test equality, we need to sort both...
此接口对实现它的每个类的对象强加一个默认排序。这种排序被称为类的自然排序,类的compareTo方法被称为其自然比较方法。 Lists (and arrays) of objects that implement this interface can be sorted automatically byCollections.sort(andArrays.sort).
2. With Sets / contains() Check: If the data in our lists are unique i.e. there isn’t a duplication, we can simply create TreeSets from the given lists and then compare them using equals(): public <T extends Comparable<T>> boolean isEquals(List<T> list1, List<T> list2){ if...
toList()); return resultList; } /** * 通过遍历两个List中按id属性相等的归结到resultList中 * @param oneList 源list 1 * @param twoList 源list 2 * @param equalKeyName 相等的map键值 */ public static List<Map<Object, Object>> compareListHitData(List<Map<Object, Object>> oneList, List...
compare(); } private static ArrayList<String> lists = new ArrayList<String>(); private static LinkedList<String> linkedLists = new LinkedList<String>(); private static HashSet<String> hashSets = new HashSet<String>(); private static HashMap<String, String> hashMaps = new HashMap<String,...
在实际项目中可能会遇到不相关的表查询结果拼装成一个并按时间倒序排序,然而这样的需求往往用sql不能方便的实现,就需要分别查询出来用List返回,但是返回时需要排序。这时就需要用到List的sort 通过实现Collections.sort的compare接口实现,可排序数字、时间,顺序、倒序 ...
面试官：RabbitMQ-如何保证消息不丢失 候选人：嗯！我们当时MYSQL和Redis的数据双写一致性就是采用Rabbit...