解析 public class Circle { double radius; public Circle(double rad) { radius = rad; } public double calcArea() { return Math.PI * radius * radius; } public static void main(String[] args) { Circle c = new Circle(3); System.out.println(c.calcArea()); } }...
在main方法中调用printAreas()方法,调用完毕后输出当前半径值。packagestudy03;publicclassCircle {privatedoubleradius;publicvoidsetRadius(doubleradius) {this.radius =radius; }publicdoublegetRadius() {returnradius; }publicdoublefindArea(){return3.14*radius*radius; } }packagestudy03;publicclassPassObject {publ...
public static void main(String[] args) { Circle c = new Circle(2.0);System.out.println("圆的面积为：" + c.area(c.r));Cylinder cl = new Cylinder(2.0, 3.0);System.out.println("圆柱体的底面积为：" + cl.area(cl.r));System.out.println("圆柱体的表面积为：" + cl...
def calculate_area_and_perimeter(r, pi): A = pi r 2 C = 2 pi r return A, C 示例:计算半径为5的圆的面积和周长 radius = 5 area, perimeter = calculate_area_and_perimeter(radius, pi) print("面积:", area) print("周长:", perimeter) 运行这段代码,将输出圆的面积和周长。CalculateTheA...
public Circle(){ super();System.out.println("输入圆的半径：");r=sc.nextDouble();setR(r);double s=getArea();System.out.println("圆的面积S="+s);} public void setR(double r){ this.r=r;} public Double getArea(){ double s=(Math.PI)*(Math.pow(this.r, 2));return s...
编写一个完整的Java Application 程序。包含接口ShapeArea,类Circle、Rectangle、Test,具体要求如下:⑴接口ShapeArea:
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CircleTest { @Test public void testGetArea() { double expectArea = 3.14D; Circle circle = PowerMockito.mock(Circle.class); PowerMockito.when(circle.getArea()).thenReturn(expectArea); double actualArea = circle.getArea(); Assert.assertEquals("返回值不相等", expectArea, actualArea, 1E-6D);...
方法: MongoDB中的集合查询(获取一组文档中某个字段的不同值列表) 运用方法:DBCollection对象方法中的 distinct() 语句: 语句结构:distinct(key,[query]) key字符串,指定获取哪个字段的不同值;query:包含标准查询选项的对象,指定了要从哪个文档
4. From the Menu, select Calc to calculate the result. 3.6.4 Running Games This application features three games: TilePuzzle, WormGame, and PushPuzzle. TilePuzzle. The desired result, "Rate your mind pal" is shown first. From the soft Menu, select Start. The scrambled puzzle is displayed...