Check Prime Number Example in Java - This program will read an integer number and check whether given number is Prime or Not, in this program we will divide number from 2 to number/2, if number divide by any number then number will not be prime number....
System.out.println("Prime check started for number: "+ crunchifyNumber); if(crunchifyNumber ==1){ return"1 is not a Prime number..."; } intlimit =(int)Math.sqrt(crunchifyNumber); for(inti =2; i<= limit; i++){ if(crunchifyNumber % i ==0){ ...
Java Code:import java.util.Scanner; public class Example17 { public static void main( String args[] ){ int num; Scanner sc = new Scanner( System.in ); System.out.print("Input a number: "); num = sc.nextInt(); int num_of_digits = 0, divisor_part=1, circular_num = num; boole...
println("Not a prime number "); } } Output: 1 2 3 Enter a number 57 Not a prime number Using Recursion 1) Read the entered number n. 2) The object for Prime class will be created in the main method. Call the method primeOrNot(n) using the object as p.primeOrNot(n); 3)...
return b1;public static void main(String args[])你显然在函数体内部开始定义另外一个函数了，return b1后面应该少了}
At the end when the algorithm terminates, all the numbers in the list that are not marked are the prime numbers. Here’s what the code looks like: publicstaticList<Integer>sieveOfEratosthenes(intn){booleanprime[] =newboolean[n +1]; Arrays.fill(prime,true);for(intp=2; p * p <= n;...
Enterany number:1919isaPrimeNumber Output 2: Enterany number:66isnotaPrimeNumber You can also usewhile loopto check the prime number: Just replace this part of the code in above program: for(inti=2;i<=num/2;i++){temp=num%i;if(temp==0){isPrime=false;break;}} ...
System.out.println(isPrime(n)?"prime":"not prime"); } } 解释: // certainty - 这一措施的调用者能容忍的不确定性:如果调用返回true,// 则此BigInteger是素数超过概率(1 - 1/2确定性)。此方法的执行时间正比于该参数的值。publicbooleanisProbablePrime(intcertainty){if(certainty <=0)returntrue;BigInte...
package com.as400samplecode; public class CheckMyNumber { public static void main(String[] args) { boolean even = false; boolean prime = true; int myNumber = Integer.parseInt(args[0].trim()); if(myNumber % 2 == 0){ even = true; ...
Java Code: importjava.util.*;publicclassExercise48{publicstaticvoidmain(String[]args){// Iterate through numbers from 1 to 99for(inti=1;i<100;i++){// Check if the number is oddif(i%2!=0){// Print the odd numberSystem.out.println(i);}}} Copy...