//功能:输出100-200之间的质数:只能被1和本身整除的数publicclassPrimeNumber{publicstaticvoidmain(String [] args){for(inti=101;i<200;i++){booleanflag=true;//标志位,当flag为true时是质数,当flag为false时不是质数for(intj=2;j<i;j++){if(i%j==0){ flag=false;break; } }/*if(flag){ Syst...
package com.day3.one; public class PrimeNumber { /** * @param args * 打印101-200之间的素数 */ public static void main(String[] args) { for(int m=101;m<=200;m++) { int count=0; for(int i=1;i<=m;i++) { if(m%i==0) count++; } if(count ==2) System.out.print(m+"...
= 100 ) // we want first 100 prime { boolean isPrime = true; // we assume that the number is prime for ( int i = 0; i < list.size(); i++ ) { if ( number % list.get(i) == 0 ) // we check for every less prime isPrime = false; // however, if it is divided by ...
public class PhoneNumber { private int areaCode; private String prefix; private String lineNumber; @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + areaCode; result = prime * result + ((lineNumber == null) ? 0 : lineNumber.hashCode(...
too much code, for too little to doLambda expression rocks !! 这个例子向我们展示了Java 8 lambda表达式的语法。你可以使用lambda写出如下代码: (params) -> expression(params) -> statement(params) -> { statements } 1. 例如,如果你的方法不对参数进行修改、重写,只是在控制台打印点东西的话,那么可以...
(Runnable r){Thread thread=newThread(r);thread.setName("PETERXX_PROJECT_POOL_"+UUID.randomUUID().toString());returnthread;}});for(int i=0;i<count;i++){threadPool.submit(newRunnable(){@Overridepublicvoidrun(){for(;;){lock.lock();for(int j=0;j<100_0000;j++){}lock.unlock();}...
Java Code: importjava.util.*;publicclassExercise48{publicstaticvoidmain(String[]args){// Iterate through numbers from 1 to 99for(inti=1;i<100;i++){// Check if the number is oddif(i%2!=0){// Print the odd numberSystem.out.println(i);}}} Copy...
// Another way to check if Number is Prime publicstaticStringcrunchifyIsPrimeNumberMethod2(intcrunchifyNumber){ System.out.println("Prime check started for number: "+ crunchifyNumber); if(crunchifyNumber ==1){ return"1 is not a Prime number..."; ...
The standard approach to solving this problem is to first take input in the code itself. The input for our given problem is an integer number. To find log in java, to make things simpler, the Math package in Java already has a built in method named log for this. ...
public class PhoneNumber { private int areaCode; private String prefix; private String lineNumber; @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + areaCode; result = prime * result + ((lineNumber == null) ? 0 : lineNumber.hashCode...