public boolean checkPerfectNumber2(intnum) {if(num<6||num%2!=0) {returnfalse; }intsum =1;for(inti=2; i<=Math.sqrt(num); i++) {if(num%i ==0) { sum += i +num/i; } }returnsum ==num; } 04 第三种解法 最小的Perfect Number是6,接着是28,然后是496 6: 2x3 true 28: 4x...
importjava.util.Scanner;publicclassPerfectNumber{publicstaticvoidmain(String[]args){Scannerscanner=newScanner(System.in);System.out.print("请输入一个正整数N:");intN=scanner.nextInt();scanner.close();for(inti=1;i<=N;i++){intsum=0;for(intj=1;j<i;j++){if(i%j==0){sum+=j;}}// ...
import java.util.Scanner;public class G { public static void perfectNumber(int n){ int f[]=new int[32]; int sum=0; int j=0; for(int i=1;i<n;i++){ if(n%i==0){ sum=sum+i; f[j]=i; j++; } } if(n==sum){ System.out.println(n...
1publicclassSolution {2publicbooleancheckPerfectNumber(intnum) {3if(num == 1){4returnfalse;5}67intsum = 1;8for(inti = 2; i<Math.sqrt(num); i++){9if(num%i == 0){10sum += i+num/i;11}12}13returnsum ==num;14}15}
4. If the sum is equal to the number, print “The number is a perfect number”. 5. If the sum is not equal to the number, print “The number is not a perfect number”. Program/Source Code Here is the source code of the Java Program to Check if a given Number is Perfect Number...
if(sum==number) System.out.println("It is Perfect Number"); elseSystem.out.println("It is not Perfect Number"); } } Output It is Perfect Number Recursive approach We can use recursion technique, if don’t want to use while loop. It reduces code statements but provides the accurate resu...
The following code implements the Simple iteration method to check whether a given number is a perfect number. 1 2 3 4 5 6 7 8 9 defperfectornot(x): s=0 foriinrange(1,x): ifx%i==0: s=s+i returns==x print(perfectornot(28)) ...
Record web requests as they happen and turn them into reusable code in any programming language. License: MIT , . Liferay plugins - The liferay-plugins repository is part of the Liferay Portal project. Liferay Portal is an open source enterprise web platform for building business solutions that...
391 Perfect Rectangle 完美矩形 TODO Hard 399 Evaluate Division 除法求值 TODO Medium 785 Is Graph Bipartite? 判断二分图 Java Medium 07.位运算 #English TitleChinese TitleSolutionDifficulty 89 Gray Code 格雷编码 TODO Medium 136 Single Number 只出现一次的数字 TODO Easy 137 Single Number II 只出现一次...
If it were a perfect source of randomly chosen bits, then the algorithm shown would choose float values from the stated range with perfect uniformity. [In early versions of Java, the result was incorrectly calculated as: text/java 複製 {@code return next(30) / ((float)(1 << 30));}...