public static double[][] multiplyByMatrix(double[][] m1, double[][] m2) { int m1ColLength = m1[0].length; // m1 columns length int m2RowLength = m2.length; // m2 rows length if (m1ColLength != m2RowLength) return null; // matrix multiplication is not possible int mRRowLength ...
public static void matrixMultiplicationTest() { int[][] tempFirstMatrix = new int[2][3]; for (int i = 0; i < tempFirstMatrix.length; i++) { for (int j = 0; j < tempFirstMatrix[0].length; j++) { tempFirstMatrix[i][j] = i + j; } // Of for j } // Of for i Sy...
public class MatrixMultiplication { public static void main(String[] args) { // 创建两个矩阵 int[][] arr1 = new int[5][4]; int[][] arr2 = new int[4][6]; // 填充数据 for (int i = 0; i < arr1.length; i++) { for (int j = 0; j < arr1[0].length; j++) { arr...
); } double[][] resultMatrix = MatrixOperations.multiply(markovMatrix, anotherMatrix); System.out.println("Result of matrix multiplication:"); for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) { System.out.printf("%.4f ", resultMatrix[i][j]); } ...
public class MatrixMultiplication { public static void main(String[] args) { int[][] matrix1 = {{1, 2}, {3, 4}}; // 第一个矩阵 int[][] matrix2 = {{1, 0}, {0, 1}}; // 第二个矩阵 int[][] result = multiply(matrix1, matrix2); // 调用矩阵乘法函数 // 打印结果 for ...
publicint[][] multiplication(int[][] matrixa,int[][] matrixb) { if(legalOperation(matrixa, matrixb, OPERATION_SUB)) { int[][] result =newint[matrixa.length][matrixb[0].length]; for(inti=0; i<matrixa.length; i++) { for(intj=0; j<matrixb[0].length; j++) { ...
栈的练习,如此水题竟然做了两个小时。。。 题意:给出矩阵大小和矩阵的运算顺序,判断能否相乘并求运算量。 我的算法很简单:比如(((DE)F)G)H)I),遇到 (就cnt累计加一,字母入栈,遇到)减一,并出栈两个矩阵计算运算量,将计算后的矩阵压入栈。当cnt等于0时就输出运算量。 难点...
publicclassMatrixMultiplication{ privatestaticfinalStringkernelCode= "extern\"C\""+"\n"+ "__global__voidmatrixMulKernel(float%2AA,float%2AB,float%2AC,intN){"+"\n"+ "introw=blockIdx.y%2AblockDim.y+threadIdx.y;"+"\n"+ "intcol=blockIdx.x%2AblockDim.x+threadIdx.x;"+"\n"+ "...
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Performs an SVD normalization of this matrix to calculate and return the uniform scale factor. int hashCode() Returns a hash code value based on the data values in this object. void invert() Inverts this matrix in place. void invert(Matrix4d m1) Sets the value of this matrix to the...