public boolean isAnagram2(Strings,Stringt) {if(s ==null|| t ==null|| s.length() != t.length()) {returnfalse; }int[] arr =newint[26];for(inti=0; i<s.length(); i++) { arr[s.charAt(i)-'a']++; arr[t.charAt(i)-'a']--; }for(intnum: arr) {if(num!=0) {return...
classSolution{publicbooleanisAnagram(String s, String t){int[] map =newint[128];char[] sArray = s.toCharArray();for(charch:sArray){ map[ch]++; }char[] tArray = t.toCharArray();for(charch:tArray){ map[ch]--; }for(intn:map){if(n !=0) {returnfalse; } }returntrue; } }...
public static void main(String[] args) { staticbooleanisAnagram(Stringa,Stringb){if(ab.length())returnfalse;int[]arr=newint[26];Stringf=a.toLowerCase();Strings=b.toLowerCase();for(inti=0;i<a.length();i++){arr[f.charAt(i)-'a']++;arr[s.charAt(i)-'a']++;}for(inti=0;i<...
CAN YOU HELP ME OUT, THIS CODE IS FAILED WITH INPUT Hello,hello ; expected output:anagram ; actual : not anagram; public static boolean isAnagram(String a,String b) { char a1[]=a.toCharArray(); char b1[]=b.toCharArray(); java.util.Arrays.sort(a1); java.util.Arrays.sort(b1);...
程序应该忽略空白和标点符号 public class Anagram { public static boolean areAnagrams(String string1, String string2) { String workingCopy1 = removeJunk(string1); String workingCopy2 = removeJunk(string2); workingCopy1 = workingCopy1.toLowerCase(); workingCopy2 = workingCopy2.toLowerCase(); ...
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public boolean isAnagram(String s, String t) { Map<Character, Integer> charCountMap = new HashMap<>(); for(char c: s.toCharArray()) { charCountMap.put(c, charCountMap.getOrDefault(c,0)+1); } for(char d: t.toCharArray()) { if(charCountMap.containsKey(d)){ int count = char...
Find Anagram Start IndicesWrite a Java program to find all the start indices of a given string's anagrams in another given string.Visual Presentation:Sample Solution:Java Code:// Importing necessary Java utilities import java.util.*; // Main class public class Main { // Main method public ...
javaCopy codepublic boolean isAnagram(String s, String t) { if (s.length() != t.length()) { return false; } int[] counter = new int[26]; // 假设只包含小写字母 for (int i = 0; i < s.length(); i++) { counter[s.charAt(i) - 'a']++; ...
leetcode T242 有效的字母异位词 给定两个字符串 s 和 t ,编写一个函数来判断 t 是否是 s 的字母异位词。 示例 1: 输入: s = “anagram”, t = “nagaram” 输出: true 示例 2: 输入: s = “rat”, t = “car” 输出: false 说明: 你可以假设字符串只包含小写字母。