public class SquareCalculator { private ExecutorService executor = Executors.newFixedThreadPool(2); //... }Copy 通过对SquareCalculator类进行简单的更改,我们现在有一个能够同时使用 2 个线程的执行器。 如果我们再次运行完全相同的客户端代码,我们将得到以下输出
public class SquareCalculator { private ExecutorService executor = Executors.newFixedThreadPool(2); //... } 1. 2. 3. 4. 5. 6. 我比较懒,你把相应的代码替换下即可,省略号那段就不用替换了。 这段代码,对 SquareCalculator 类的做了一处简单的更改,使得我们的执行器拥有了 2 个同步线程。 如果我们...
假设我们有以下Java代码,目的是计算一个数组中所有元素的平方和: publicclassSquareSum{publicstaticvoidmain(String[]args){int[]numbers={1,2,3,4,5};intresult=calculateSquareSum(numbers);System.out.println("Square Sum: "+result);}publicstaticintcalculateSquareSum(int[]nums){intsum=0;for(intnum:nu...
import java.util.concurrent.ThreadPoolExecutor; public class JavaFutureEx { public static void main(String[] args) throws ExecutionException, InterruptedException { var executor = (ThreadPoolExecutor) Executors.newFixedThreadPool(2); var random = new Random(); for (int i = 0; i < 6; i++)...
publicclassSquareCalculator{privateExecutorService executor = Executors.newFixedThreadPool(2);//...} 通过对SquareCalculator类的简单更改,我们现在有一个执行器,它可以使用2个同步线程。 如果我们再次运行完全相同的客户端代码,我们将获得以下输出: calculating squarefor: 10 ...
public class SquareCalculator { private ExecutorService executor = Executors.newFixedThreadPool(2); //... } 现在我们有了一个能够同时使用两个线程的执行器。如果我们再次运行完全相同的客户机代码,我们将得到以下输出 calculating square for: 10 calculating square for: 100 future1 is not done and future...
//Calculating square root of even numbers from 1 to N int min = 1; int max = 1000000; List<Integer> sourceList = new ArrayList<>(); for (int i = min; i < max; i++) { sourceList.add(i); } List<Double> result = new LinkedList<>(); ...
i<num.length;i++){output[i]=num[i]*num[i];//Calculating Square of entered numbers}for(int...
for (int i = 0; i < numTasks; i++) { executor.submit(() -> { // 模拟一个耗时任务,随机生成一个数并计算其平方 int randomNum = ThreadLocalRandom.current().nextInt(100); System.out.println("Thread " + Thread.currentThread().getName() + " calculating square of " + randomNum); ...
publicclassJavaExample{publicvoidcalculate(intp,intt,doubler,intn){doubleamount=p * Math.pow(1+ (r / n), n * t);doublecinterest=amount - p; System.out.println("Compound Interest after "+ t +" years: "+cinterest); System.out.println("Amount after "+ t +" years: "+amount); ...