publicclassCheckStringInArray{publicstaticvoidmain(String[]args){String[]fruits={"apple","banana","orange","grape","watermelon"};Stringtarget="orange";booleanfound=false;for(Stringfruit:fruits){if(fruit.equals(target)){found=true;break;}}if(found){System.out.println(target+" is in the arr...
publicclassMain{publicstaticvoidmain(String[]args){String[]array={"apple","banana","cherry"};Stringtarget="banana";booleanfound=false;for(Stringstr:array){if(str.equals(target)){found=true;break;}}if(found){System.out.println(target+" is in the array.");}else{System.out.println(target+...
Step 1: Create a boolean array of size 26 to track the presence of each letter. Step 2: We first assume the given string is a pangram. For this, initialize an integer flag to 1. Step 3: Iterate through each character in the String using Loop. Step 4: If the character is a letter...
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if (element == toCheckValue) { test = true; break; } } System.out.println("Is " + toCheckValue + " present in the array: " + test); } public static void main(String[] args) { int arr[] = {5, 1, 1, 9, 7, 2, 6, 10}; ...
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* @return 是否为数组对象,如果为{@code null} 返回false */publicstaticbooleanisArray(Object obj){if(null==obj){// throw new NullPointerException("Object check for isArray is null");returnfalse;}// 反射 获得类型returnobj.getClass().isArray();}...
To check if a String is numeric in Java, you can use the isNumeric method of the StringUtils class from the org.apache.commons.lang3 library.
1.1 Check if a String Array contains a certain value “A”. StringArrayExample1.java package com.mkyong.core; import java.util.Arrays; import java.util.List; public class StringArrayExample1 { public static void main(String[] args) { ...
1.1 Check if a String Array contains a certain value “A”. StringArrayExample1.java package com.mkyong.core; import java.util.Arrays; import java.util.List; public class StringArrayExample1 { public static void main(String[] args) { ...