";StringsubStr="Java";if(str.contains(subStr)){intstartIndex=str.indexOf(subStr);intendIndex=startIndex+subStr.length()-1;System.out.println("Start Index: "+startIndex);System.out.println("End Index: "+endIndex);}else{System.out.println("Substring not found.");}}} 1. 2. 3. 4. 5...
Sample Output: Input first string: Once in a blue moon Input second string: See eye to eye If the second string contains the first one? false Flowchart: For more Practice: Solve these Related Problems:Write a Java program to count the occurrences of a given substring within another string. ...
下面是一个完整的Java代码示例,展示了如何在Java String中判断是否包含指定字符串。 publicclassStringContainsExample{publicstaticvoidmain(String[]args){Stringstr="Hello World";StringsubStr="Hello";booleancontains=checkIfStringContains(str,subStr);System.out.println("String contains specified substring: "+cont...
classMain{publicstaticvoidmain(String[] args){ String str1 ="program";// 1st character to the last character System.out.println(str1.substring(0));// program // 4th character to the last characterSystem.out.println(str1.substring(3));// gram} } Run Code Example 2: Java substring() ...
JDK 7 中的substring 上述问题在JDK 7中得到了解决。JDK 7中,substring方法会在堆中创建一个新的数组。 源码 //JDK 7 /** * Allocates a new {@codeString} that contains characters from a subarray * of the character array argument. The {@codeoffset} argument is the ...
if (s.contains(c)) { } 使用String.indexOf方法判断是否包含某个子串 int indexOf(String str) Returns the index within this string of the first occurrence of the specified substring. if (str.indexOf(sub) >= 0) { // do something
Home Question how to check if string contains '+' character You need this instead:if(s.contains("+")) contains() method of String class does not take regular expression as a parameter, it takes normal text.EDIT:String s = "ddjdjdj+kfkfkf"; if(s.contains("+")) { String parts[] ...
1. String Starts with Specified Prefix or Value JavaString.startsWith()method checks if a string begins with the specified prefix substring. The argument prefix must be a standard substring and the regular expressions are not supported. ThestartsWith()method is an overloaded method and has two ...
Example 1: Check if String is Empty or Null class Main { public static void main(String[] args) { // create null, empty, and regular strings String str1 = null; String str2 = ""; String str3 = " "; // check if str1 is null or empty System.out.println("str1 is " + is...
public String substring(int beginIndex, int endIndex) { int length = length(); checkBoundsBeginEnd(beginIndex, endIndex, length); int subLen = endIndex - beginIndex; if (beginIndex == 0 && endIndex == length) { return this; }