for(Map.Entry<Integer,Integer>entry:map.entrySet()){if(entry.getValue()>1){System.out.println("重复元素:"+entry.getKey()+",次数:"+entry.getValue());}} 1. 2. 3. 4. 5. 4. 类图 ArrayDuplicate- nums: int[]- map: HashMap+main(String[] args) : void+findDuplicates() : void 5...
可能太长了。例如：string[]texts=new string[array.length]；int[]counts=新int[array.length]；一个...
classSolution {publicList<Integer> findDuplicates(int[] nums) { List<Integer> res =newArrayList<>();if(nums ==null|| nums.length == 0)returnres;for(inti = 0; i < nums.length; i++) {intindex = Math.abs(nums[i]) - 1;if(nums[index] > 0) nums[index] *= -1;else{ res.add...
通过题主的描述可以看到，其实就是一个List<Integer>的集合数据处理问题，希望把相同的数据放到一起，是一种归类操作，也就是说其实总得需要把List<Integer>形式转化为Map<Integer, List<Integer>>的形式 这种形式map的key也就是当前的这个数字，而这个value就是这个数字对应的所有当前出现此key的集合 Li...
publicclassSolution{publicintremoveDuplicates(int[]A){intcount=0;if(A==null||A.length==0){returncount;}count=1;// 从索引1开始遍历,获得不重复个数for(inti=1;i<A.length;i++){if(A[i]!=A[i-1]){count++;}}intuniqueIndex=1;// 记录已经有了多少个不重复的数字被换到了前面for(inti=1;...
Elements{publicstaticvoidmain(String[]args){int[]array={1,2,3,4,2,5,6,3};HashSet<Integer>set=newHashSet<>();HashSet<Integer>duplicates=newHashSet<>();for(inti:array){if(!set.add(i)){duplicates.add(i);}}System.out.println("Duplicate elements in the array are: "+duplicates);}}...
leetcode442. Find All Duplicates in an Array 题目要求 Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array.
原题链接在这里:https://leetcode.com/problems/find-all-duplicates-in-an-array/ 题目: Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without...
There are multiple ways to do this, you can follow the approach we used forremoving duplicates from array in Java, where we loop through array and inserting each element in a Set, which ensures that we discard duplicate because Set doesn't allow them to insert, or you can also use remove...
public Object[] toArray(){ } Parameter(s) It does not accept any parameter. Return value The return type of this method isObject[], it returns a converted ArrayList to an Array which contains all of the elements in the ArrayList.