List<String> list = Arrays.asList("a", "b", "c"); List<String> equalList = Arrays.asList("b", "c", "a"); List<String> unequalList = Arrays.asList("d", "c", "a"); assertTrue(CollectionUtils.isEqualCollection(list, equalList)); assertFalse(CollectionUtils.isEqualCollection(list...
.filter(item -> listTwo.contains(item)) .toList(); Assertions.assertTrue(CollectionUtils.isEqualCollection(List.of("a", "b"), listOfCommonItems)); 此外,还可以使用CollectionUtils.intersection()方法,它返回两个列表中的共同元素。 List<String> listOfCommonItems = (List<String>) CollectionUtils.int...
"banana","orange"));// 需要判断的元素StringelementToCheck="banana";// 使用assert来检查元素是否在集合中assertitems.contains(elementToCheck):elementToCheck+" is not found in the list";System.out.println
when(mockedList.contains(argThat(isValid())).thenReturn("element"); // 输出element System.out.println(mockedList.get(999)); // 也可以验证参数匹配器 verify(mockedList).get(anyInt()); verify(mock).someMethod(anyInt(), anyString(), eq("third argument")); // 上述代码是正确的, 因为eq()...
contains:是否包含某字符串 addAll:添加整个数组 clone:克隆一个数组 isEmpty:是否空数组 add:向数组添加元素 subarray:截取数组 indexOf:查找某个元素的下标 isEquals:比较数组是否相等 toObject:基础类型数据数组转换为对应的Object数组 1.5 org.apache.commons.lang3.ArrayUtils ...
void linkBefore(E e, Node<E> succ) { // assert succ != null; // 获取当前节点的前面一个节点 final Node<E> pred = succ.prev; // 创建一个新节点,e它的前面一个节点指针指向前面一个节点pred,后面一个节点指向succ final Node<E> newNode = new Node<>(pred, e, succ); // succ的前面...
ArrayList<String> expectList = ["1","5","6"] containsList(actualList, expectList )//Check the expectList in actualListstaticdef containsList(ArrayList<String> actualList, ArrayList<String>expectList){if(actualList.containsAll(expectList)){asserttrue}else{ ...
String x = "foo bar"; Assert.assertThat(x, CoreMatchers.containsString("foo")); 通过一些静态导入,它看起来好多了: assertThat(x, containsString("foo")); 所需的静态导入是: import static org.hamcrest.MatcherAssert.assertThat; import static org.hamcrest.CoreMatchers.containsString; 原文由 Yi...
assertThat(list).isNotEmpty().contains("1").doesNotContainNull().containsSequence("2","3"); 当然,对于那些类型存在更多可能的断言 。具体请参阅官方的AbstractIterableAssertAPI 完整示例: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 @Test(description="Iterable/Array断言1")publicvoidwhenCheckingFo...
// assert x != null; final E element = x.item; final Node<E> next = x.next; final Node<E> prev = x.prev; if (prev == null) { first = next; } else { prev.next = next; x.prev = null; } if (next == null) { ...