// API对接代码示例@RestController@RequestMapping("/sort")publicclassSortController{@PostMapping("/desc")publicResponseEntity<int[]>sortDescending(@RequestBodyint[]arr){// 调用排序方法returnResponseEntity.ok(newArraySorter().sortDescending(arr));}} 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 以上内容...
// 排序方法publicstaticvoidsortArrayDescending(int[]array){intn=array.length;// 外层循环控制排序的趟数for(inti=0;i<n-1;i++){// 假设当前的最大值是当前位置intmaxIndex=i;// 内层循环寻找未排序部分的最大值for(intj=i+1;j<n;j++){if(array[j]>array[maxIndex]){maxIndex=j;// 更新最...
import java.util.Arrays; public class SortDescendingLambdaExample { public static void main(String[] args) { int[] nums = {4, 32, 45, 32, 65, 32, 2}; Integer[] numsInteger = Arrays.stream(nums).boxed().toArray(Integer[]::new); // 使用Lambda表达式和Comparator接口实现从大到小的排序...
// Checkifthe array is nearly sortedfor(int k = left; k < right; run[count] = k) {if(a[k] < a[k + 1]) { // ascendingwhile(++k <= right && a[k - 1] <= a[k]); }elseif(a[k] > a[k + 1]) { // descendingwhile(++k <= right && a[k - 1] >= a[k]);fo...
public class DescendingSortExample { public static void main(String[] args) { Integer[] array = {5, 2, 9, 1, 5, 6}; // 方法一:使用Arrays.sort()和自定义Comparator Arrays.sort(array, new Comparator<Integer>() { @Override public int compare(Integer o1, Integer o2) { ...
Learn to sort Java ArrayList in ascending and descending order using ArrayList.sort(), Collections.sort(), Comparator interface and Java 8 Streams.
在代码执行的过程中SortedOps.java类中 Arrays.sort(array, 0, offset, comparator); 执行了Array集合类型的sort排序算法。 @Override public void end() { Arrays.sort(array, 0, offset, comparator); downstream.begin(offset); if (!cancellationWasRequested) { ...
// Check if the array is nearly sorted for (int k = left; k < right; run[count] = k) { if (a[k] < a[k + 1]) { // ascending while (++k <= right && a[k - 1] <= a[k]); } else if (a[k] > a[k + 1]) { // descending ...
sort(a, left, right, true); return; } /* * Index run[i] is the start of i-th run * (ascending or descending sequence). */ int[] run = new int[MAX_RUN_COUNT + 1]; int count = 0; run[0] = left; // Check if the array is nearly sorted ...
// If array is small, do a "mini-TimSort" with no merges if (nRemaining < MIN_MERGE) { int initRunLen = countRunAndMakeAscending(a, lo, hi, c); binarySort(a, lo, hi, lo + initRunLen, c); return; } 1. 2. 3. 4. ...